leetcode-problemset/leetcode-cn/originData/sum-of-matrix-after-queries.json

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            "title": "Sum of Matrix After Queries",
            "titleSlug": "sum-of-matrix-after-queries",
            "content": "<p>You are given an integer <code>n</code> and a <strong>0-indexed</strong>&nbsp;<strong>2D array</strong> <code>queries</code> where <code>queries[i] = [type<sub>i</sub>, index<sub>i</sub>, val<sub>i</sub>]</code>.</p>\n\n<p>Initially, there is a <strong>0-indexed</strong> <code>n x n</code> matrix filled with <code>0</code>&#39;s. For each query, you must apply one of the following changes:</p>\n\n<ul>\n\t<li>if <code>type<sub>i</sub> == 0</code>, set the values in the row with <code>index<sub>i</sub></code> to <code>val<sub>i</sub></code>, overwriting any previous values.</li>\n\t<li>if <code>type<sub>i</sub> == 1</code>, set the values in the column with <code>index<sub>i</sub></code> to <code>val<sub>i</sub></code>, overwriting any previous values.</li>\n</ul>\n\n<p>Return <em>the sum of integers in the matrix after all queries are applied</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/11/exm1.png\" style=\"width: 681px; height: 161px;\" />\n<pre>\n<strong>Input:</strong> n = 3, queries = [[0,0,1],[1,2,2],[0,2,3],[1,0,4]]\n<strong>Output:</strong> 23\n<strong>Explanation:</strong> The image above describes the matrix after each query. The sum of the matrix after all queries are applied is 23. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/11/exm2.png\" style=\"width: 681px; height: 331px;\" />\n<pre>\n<strong>Input:</strong> n = 3, queries = [[0,0,4],[0,1,2],[1,0,1],[0,2,3],[1,2,1]]\n<strong>Output:</strong> 17\n<strong>Explanation:</strong> The image above describes the matrix after each query. The sum of the matrix after all queries are applied is 17.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>queries[i].length == 3</code></li>\n\t<li><code>0 &lt;= type<sub>i</sub> &lt;= 1</code></li>\n\t<li><code>0 &lt;= index<sub>i</sub>&nbsp;&lt; n</code></li>\n\t<li><code>0 &lt;= val<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "查询后矩阵的和",
            "translatedContent": "<p>给你一个整数&nbsp;<code>n</code>&nbsp;和一个下标从 <strong>0</strong>&nbsp;开始的 <strong>二维数组</strong>&nbsp;<code>queries</code>&nbsp;，其中&nbsp;<code>queries[i] = [type<sub>i</sub>, index<sub>i</sub>, val<sub>i</sub>]</code>&nbsp;。</p>\n\n<p>一开始，给你一个下标从 <strong>0</strong>&nbsp;开始的&nbsp;<code>n x n</code>&nbsp;矩阵，所有元素均为 <code>0</code>&nbsp;。每一个查询，你需要执行以下操作之一：</p>\n\n<ul>\n\t<li>如果&nbsp;<code>type<sub>i</sub> == 0</code>&nbsp;，将第&nbsp;<code>index<sub>i</sub></code>&nbsp;行的元素全部修改为&nbsp;<code>val<sub>i</sub></code>&nbsp;，覆盖任何之前的值。</li>\n\t<li>如果&nbsp;<code>type<sub>i</sub> == 1</code>&nbsp;，将第&nbsp;<code>index<sub>i</sub></code>&nbsp;列的元素全部修改为 <code>val<sub>i</sub></code>&nbsp;，覆盖任何之前的值。</li>\n</ul>\n\n<p>请你执行完所有查询以后，返回矩阵中所有整数的和。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/11/exm1.png\" style=\"width: 681px; height: 161px;\"></p>\n\n<pre><b>输入：</b>n = 3, queries = [[0,0,1],[1,2,2],[0,2,3],[1,0,4]]\n<b>输出：</b>23\n<b>解释：</b>上图展示了每个查询以后矩阵的值。所有操作执行完以后，矩阵元素之和为 23 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/05/11/exm2.png\" style=\"width: 681px; height: 331px;\"></p>\n\n<pre><b>输入：</b>n = 3, queries = [[0,0,4],[0,1,2],[1,0,1],[0,2,3],[1,2,1]]\n<b>输出：</b>17\n<b>解释：</b>上图展示了每一个查询操作之后的矩阵。所有操作执行完以后，矩阵元素之和为 17 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>queries[i].length == 3</code></li>\n\t<li><code>0 &lt;= type<sub>i</sub> &lt;= 1</code></li>\n\t<li><code>0 &lt;= index<sub>i</sub>&nbsp;&lt; n</code></li>\n\t<li><code>0 &lt;= val<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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