leetcode-problemset/leetcode-cn/originData/sleep.json

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            "questionId": "2733",
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            "categoryTitle": "JavaScript",
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            "title": "Sleep",
            "titleSlug": "sleep",
            "content": "<p>Given&nbsp;a positive integer <code>millis</code>, write an asynchronous function that sleeps for <code>millis</code>&nbsp;milliseconds. It can resolve any value.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> millis = 100\n<strong>Output:</strong> 100\n<strong>Explanation:</strong> It should return a promise that resolves after 100ms.\nlet t = Date.now();\nsleep(100).then(() =&gt; {\n  console.log(Date.now() - t); // 100\n});\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> millis = 200\n<strong>Output:</strong> 200\n<strong>Explanation:</strong> It should return a promise that resolves after 200ms.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= millis &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "睡眠函数",
            "translatedContent": "<p>请你编写一个异步函数，它接收一个正整数参数 <code>millis</code>&nbsp;，并休眠 <code>millis</code> 毫秒。要求此函数可以解析任何值。</p>\n\n<p>&nbsp;</p>\n\n<p><b>示例 1：</b></p>\n\n<pre>\n<b>输入：</b>millis = 100\n<b>输出：</b>100\n<b>解释：</b>\n在 100ms 后此异步函数执行完时返回一个 Promise 对象\nlet t = Date.now();\nsleep(100).then(() =&gt; {\n  console.log(Date.now() - t); // 100\n});\n</pre>\n\n<p><b>示例 2：</b></p>\n\n<pre>\n<b>输入：</b>millis = 200\n<b>输出：</b>200\n<b>解释：</b>在 200ms 后函数执行完时返回一个 Promise 对象\n</pre>\n\n<p>&nbsp;</p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>1 &lt;= millis &lt;= 1000</code></li>\n</ul>\n",
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                    "lang": "JavaScript",
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                    "code": "/**\n * @param {number} millis\n * @return {Promise}\n */\nasync function sleep(millis) {\n    \n}\n\n/** \n * let t = Date.now()\n * sleep(100).then(() => console.log(Date.now() - t)) // 100\n */",
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                    "code": "async function sleep(millis: number): Promise<void> {\n    \n}\n\n\n/** \n * let t = Date.now()\n * sleep(100).then(() => console.log(Date.now() - t)) // 100\n */",
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            "hints": [
                "In Javascript, you can execute code after some delay with the setTimeout(fn, sleepTime) function.",
                "An async function is defined as function which returns a Promise.",
                "To create a Promise, you can code new Promise((resolve, reject) => {}). When you want the function to return a value, code resolve(value) inside the callback."
            ],
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