leetcode-problemset/leetcode-cn/originData/shifting-letters-ii.json

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            "title": "Shifting Letters II",
            "titleSlug": "shifting-letters-ii",
            "content": "<p>You are given a string <code>s</code> of lowercase English letters and a 2D integer array <code>shifts</code> where <code>shifts[i] = [start<sub>i</sub>, end<sub>i</sub>, direction<sub>i</sub>]</code>. For every <code>i</code>, <strong>shift</strong> the characters in <code>s</code> from the index <code>start<sub>i</sub></code> to the index <code>end<sub>i</sub></code> (<strong>inclusive</strong>) forward if <code>direction<sub>i</sub> = 1</code>, or shift the characters backward if <code>direction<sub>i</sub> = 0</code>.</p>\n\n<p>Shifting a character <strong>forward</strong> means replacing it with the <strong>next</strong> letter in the alphabet (wrapping around so that <code>&#39;z&#39;</code> becomes <code>&#39;a&#39;</code>). Similarly, shifting a character <strong>backward</strong> means replacing it with the <strong>previous</strong> letter in the alphabet (wrapping around so that <code>&#39;a&#39;</code> becomes <code>&#39;z&#39;</code>).</p>\n\n<p>Return <em>the final string after all such shifts to </em><code>s</code><em> are applied</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abc&quot;, shifts = [[0,1,0],[1,2,1],[0,2,1]]\n<strong>Output:</strong> &quot;ace&quot;\n<strong>Explanation:</strong> Firstly, shift the characters from index 0 to index 1 backward. Now s = &quot;zac&quot;.\nSecondly, shift the characters from index 1 to index 2 forward. Now s = &quot;zbd&quot;.\nFinally, shift the characters from index 0 to index 2 forward. Now s = &quot;ace&quot;.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;dztz&quot;, shifts = [[0,0,0],[1,1,1]]\n<strong>Output:</strong> &quot;catz&quot;\n<strong>Explanation:</strong> Firstly, shift the characters from index 0 to index 0 backward. Now s = &quot;cztz&quot;.\nFinally, shift the characters from index 1 to index 1 forward. Now s = &quot;catz&quot;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, shifts.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>shifts[i].length == 3</code></li>\n\t<li><code>0 &lt;= start<sub>i</sub> &lt;= end<sub>i</sub> &lt; s.length</code></li>\n\t<li><code>0 &lt;= direction<sub>i</sub> &lt;= 1</code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "字母移位 II",
            "translatedContent": "<p>给你一个小写英文字母组成的字符串&nbsp;<code>s</code>&nbsp;和一个二维整数数组&nbsp;<code>shifts</code>&nbsp;，其中&nbsp;<code>shifts[i] = [start<sub>i</sub>, end<sub>i</sub>, direction<sub>i</sub>]</code>&nbsp;。对于每个&nbsp;<code>i</code>&nbsp;，将&nbsp;<code>s</code>&nbsp;中从下标&nbsp;<code>start<sub>i</sub></code>&nbsp;到下标&nbsp;<code>end<sub>i</sub></code>&nbsp;（两者都包含）所有字符都进行移位运算，如果&nbsp;<code>direction<sub>i</sub> = 1</code>&nbsp;将字符向后移位，如果&nbsp;<code>direction<sub>i</sub> = 0</code>&nbsp;将字符向前移位。</p>\n\n<p>将一个字符 <strong>向后</strong>&nbsp;移位的意思是将这个字符用字母表中 <strong>下一个</strong>&nbsp;字母替换（字母表视为环绕的，所以&nbsp;<code>'z'</code>&nbsp;变成&nbsp;<code>'a'</code>）。类似的，将一个字符 <strong>向前</strong>&nbsp;移位的意思是将这个字符用字母表中 <strong>前一个</strong>&nbsp;字母替换（字母表是环绕的，所以&nbsp;<code>'a'</code>&nbsp;变成&nbsp;<code>'z'</code>&nbsp;）。</p>\n\n<p>请你返回对 <code>s</code>&nbsp;进行所有移位操作以后得到的最终字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>s = \"abc\", shifts = [[0,1,0],[1,2,1],[0,2,1]]\n<b>输出：</b>\"ace\"\n<b>解释：</b>首先，将下标从 0 到 1 的字母向前移位，得到 s = \"zac\" 。\n然后，将下标从 1 到 2 的字母向后移位，得到 s = \"zbd\" 。\n最后，将下标从 0 到 2 的字符向后移位，得到 s = \"ace\" 。</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><b>输入：</b>s = \"dztz\", shifts = [[0,0,0],[1,1,1]]\n<b>输出：</b>\"catz\"\n<b>解释：</b>首先，将下标从 0 到 0 的字母向前移位，得到 s = \"cztz\" 。\n最后，将下标从 1 到 1 的字符向后移位，得到 s = \"catz\" 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, shifts.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>shifts[i].length == 3</code></li>\n\t<li><code>0 &lt;= start<sub>i</sub> &lt;= end<sub>i</sub> &lt; s.length</code></li>\n\t<li><code>0 &lt;= direction<sub>i</sub> &lt;= 1</code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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                "Instead of shifting every character in each shift, could you keep track of which characters are shifted and by how much across all shifts?",
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