leetcode-problemset/leetcode-cn/originData/rotate-matrix-lcci.json

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            "questionId": "100185",
            "questionFrontendId": "面试题 01.07",
            "categoryTitle": "LCCI",
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            "title": "Rotate Matrix LCCI",
            "titleSlug": "rotate-matrix-lcci",
            "content": "<p>Given an image represented by an N x N matrix, where each pixel in the image is 4 bytes, write a method to rotate the image by 90 degrees. Can you do this in place?</p>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\nGiven <strong>matrix</strong> = \r\n[\r\n  [1,2,3],\r\n  [4,5,6],\r\n  [7,8,9]\r\n],\r\n\r\nRotate the matrix <strong>in place. </strong>It becomes:\r\n[\r\n  [7,4,1],\r\n  [8,5,2],\r\n  [9,6,3]\r\n]\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\nGiven <strong>matrix</strong> =\r\n[\r\n  [ 5, 1, 9,11],\r\n  [ 2, 4, 8,10],\r\n  [13, 3, 6, 7],\r\n  [15,14,12,16]\r\n], \r\n\r\nRotate the matrix <strong>in place. </strong>It becomes:\r\n[\r\n  [15,13, 2, 5],\r\n  [14, 3, 4, 1],\r\n  [12, 6, 8, 9],\r\n  [16, 7,10,11]\r\n]\r\n</pre>\r\n",
            "translatedTitle": "旋转矩阵",
            "translatedContent": "<p>给你一幅由 <code>N × N</code> 矩阵表示的图像，其中每个像素的大小为 4 字节。请你设计一种算法，将图像旋转 90 度。</p>\n\n<p>不占用额外内存空间能否做到？</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n给定 <strong>matrix</strong> = \n[\n  [1,2,3],\n  [4,5,6],\n  [7,8,9]\n],\n\n<strong>原地</strong>旋转输入矩阵，使其变为:\n[\n  [7,4,1],\n  [8,5,2],\n  [9,6,3]\n]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n给定 <strong>matrix</strong> =\n[\n  [ 5, 1, 9,11],\n  [ 2, 4, 8,10],\n  [13, 3, 6, 7],\n  [15,14,12,16]\n], \n\n<strong>原地</strong>旋转输入矩阵，使其变为:\n[\n  [15,13, 2, 5],\n  [14, 3, 4, 1],\n  [12, 6, 8, 9],\n  [16, 7,10,11]\n]\n</pre>\n\n<p><strong>注意</strong>：本题与主站 48 题相同：<a href=\"https://leetcode-cn.com/problems/rotate-image/\">https://leetcode-cn.com/problems/rotate-image/</a></p>\n",
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                    "code": "/**\n * @param {number[][]} matrix\n * @return {void} Do not return anything, modify matrix in-place instead.\n */\nvar rotate = function(matrix) {\n\n};",
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                    "code": "# @param {Integer[][]} matrix\n# @return {Void} Do not return anything, modify matrix in-place instead.\ndef rotate(matrix)\n\nend",
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            "hints": [
                "尝试逐层思考。你能旋转某个特定图层吗？",
                "旋转一个特定的层只意味着在4个数组中交换值。如果要求你在2个数组中交换值，你能做到吗？你能把它扩展到4个数组吗？"
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