leetcode-problemset/leetcode-cn/originData/odd-even-linked-list.json

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        "question": {
            "questionId": "328",
            "questionFrontendId": "328",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1679,
            "title": "Odd Even Linked List",
            "titleSlug": "odd-even-linked-list",
            "content": "<p>Given the <code>head</code> of a singly linked list, group all the nodes with odd indices together followed by the nodes with even indices, and return <em>the reordered list</em>.</p>\n\n<p>The <strong>first</strong> node is considered <strong>odd</strong>, and the <strong>second</strong> node is <strong>even</strong>, and so on.</p>\n\n<p>Note that the relative order inside both the even and odd groups should remain as it was in the input.</p>\n\n<p>You must solve the problem&nbsp;in <code>O(1)</code>&nbsp;extra space complexity and <code>O(n)</code> time complexity.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/10/oddeven-linked-list.jpg\" style=\"width: 300px; height: 123px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2,3,4,5]\n<strong>Output:</strong> [1,3,5,2,4]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/10/oddeven2-linked-list.jpg\" style=\"width: 500px; height: 142px;\" />\n<pre>\n<strong>Input:</strong> head = [2,1,3,5,6,4,7]\n<strong>Output:</strong> [2,3,6,7,1,5,4]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the linked list is in the range <code>[0, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-10<sup>6</sup> &lt;= Node.val &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
            "translatedTitle": "奇偶链表",
            "translatedContent": "<p>给定单链表的头节点&nbsp;<code>head</code>&nbsp;，将所有索引为奇数的节点和索引为偶数的节点分别组合在一起，然后返回重新排序的列表。</p>\n\n<p><strong>第一个</strong>节点的索引被认为是 <strong>奇数</strong> ， <strong>第二个</strong>节点的索引为&nbsp;<strong>偶数</strong> ，以此类推。</p>\n\n<p>请注意，偶数组和奇数组内部的相对顺序应该与输入时保持一致。</p>\n\n<p>你必须在&nbsp;<code>O(1)</code>&nbsp;的额外空间复杂度和&nbsp;<code>O(n)</code>&nbsp;的时间复杂度下解决这个问题。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/03/10/oddeven-linked-list.jpg\" style=\"height: 123px; width: 300px;\" /></p>\n\n<pre>\n<strong>输入: </strong>head = [1,2,3,4,5]\n<strong>输出:</strong>&nbsp;[1,3,5,2,4]</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/03/10/oddeven2-linked-list.jpg\" style=\"height: 142px; width: 500px;\" /></p>\n\n<pre>\n<strong>输入:</strong> head = [2,1,3,5,6,4,7]\n<strong>输出:</strong> [2,3,6,7,1,5,4]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n ==&nbsp;</code> 链表中的节点数</li>\n\t<li><code>0 &lt;= n &lt;= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>6</sup>&nbsp;&lt;= Node.val &lt;= 10<sup>6</sup></code></li>\n</ul>\n",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    ListNode* oddEvenList(ListNode* head) {\n\n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public ListNode oddEvenList(ListNode head) {\n\n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def oddEvenList(self, head):\n        \"\"\"\n        :type head: ListNode\n        :rtype: ListNode\n        \"\"\"\n        ",
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                    "code": "# Definition for singly-linked list.\n# class ListNode:\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution:\n    def oddEvenList(self, head: Optional[ListNode]) -> Optional[ListNode]:",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\nstruct ListNode* oddEvenList(struct ListNode* head) {\n    \n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public ListNode OddEvenList(ListNode head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {ListNode}\n */\nvar oddEvenList = function(head) {\n\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction oddEvenList(head: ListNode | null): ListNode | null {\n    \n};",
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                    "code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n *     public $val = 0;\n *     public $next = null;\n *     function __construct($val = 0, $next = null) {\n *         $this->val = $val;\n *         $this->next = $next;\n *     }\n * }\n */\nclass Solution {\n\n    /**\n     * @param ListNode $head\n     * @return ListNode\n     */\n    function oddEvenList($head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public var val: Int\n *     public var next: ListNode?\n *     public init() { self.val = 0; self.next = nil; }\n *     public init(_ val: Int) { self.val = val; self.next = nil; }\n *     public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n    func oddEvenList(_ head: ListNode?) -> ListNode? {\n\n    }\n}",
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                    "code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n *     var next: ListNode? = null\n * }\n */\nclass Solution {\n    fun oddEvenList(head: ListNode?): ListNode? {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *   int val;\n *   ListNode? next;\n *   ListNode([this.val = 0, this.next]);\n * }\n */\nclass Solution {\n  ListNode? oddEvenList(ListNode? head) {\n    \n  }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc oddEvenList(head *ListNode) *ListNode {\n\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode\n#     attr_accessor :val, :next\n#     def initialize(val = 0, _next = nil)\n#         @val = val\n#         @next = _next\n#     end\n# end\n# @param {ListNode} head\n# @return {ListNode}\ndef odd_even_list(head)\n\nend",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n *   var next: ListNode = _next\n *   var x: Int = _x\n * }\n */\nobject Solution {\n    def oddEvenList(head: ListNode): ListNode = {\n\n    }\n}",
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                    "code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n//   pub val: i32,\n//   pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n//   #[inline]\n//   fn new(val: i32) -> Self {\n//     ListNode {\n//       next: None,\n//       val\n//     }\n//   }\n// }\nimpl Solution {\n    pub fn odd_even_list(head: Option<Box<ListNode>>) -> Option<Box<ListNode>> {\n\n    }\n}",
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                    "lang": "Racket",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (odd-even-list head)\n  (-> (or/c list-node? #f) (or/c list-node? #f))\n  )",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec odd_even_list(Head :: #list_node{} | null) -> #list_node{} | null.\nodd_even_list(Head) ->\n  .",
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                    "code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           next: ListNode.t() | nil\n#         }\n#   defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n  @spec odd_even_list(head :: ListNode.t | nil) :: ListNode.t | nil\n  def odd_even_list(head) do\n    \n  end\nend",
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