mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
177 lines
21 KiB
JSON
177 lines
21 KiB
JSON
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"questionId": "1520",
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"categoryTitle": "Algorithms",
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"boundTopicId": 185632,
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"title": "Number of Steps to Reduce a Number in Binary Representation to One",
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"content": "<p>Given the binary representation of an integer as a string <code>s</code>, return <em>the number of steps to reduce it to </em><code>1</code><em> under the following rules</em>:</p>\n\n<ul>\n\t<li>\n\t<p>If the current number is even, you have to divide it by <code>2</code>.</p>\n\t</li>\n\t<li>\n\t<p>If the current number is odd, you have to add <code>1</code> to it.</p>\n\t</li>\n</ul>\n\n<p>It is guaranteed that you can always reach one for all test cases.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "1101"\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> "1101" corressponds to number 13 in their decimal representation.\nStep 1) 13 is odd, add 1 and obtain 14. \nStep 2) 14 is even, divide by 2 and obtain 7.\nStep 3) 7 is odd, add 1 and obtain 8.\nStep 4) 8 is even, divide by 2 and obtain 4. \nStep 5) 4 is even, divide by 2 and obtain 2. \nStep 6) 2 is even, divide by 2 and obtain 1. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "10"\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> "10" corressponds to number 2 in their decimal representation.\nStep 1) 2 is even, divide by 2 and obtain 1. \n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "1"\n<strong>Output:</strong> 0\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 500</code></li>\n\t<li><code>s</code> consists of characters '0' or '1'</li>\n\t<li><code>s[0] == '1'</code></li>\n</ul>\n",
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"translatedTitle": "将二进制表示减到 1 的步骤数",
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"translatedContent": "<p>给你一个以二进制形式表示的数字 <code>s</code> 。请你返回按下述规则将其减少到 1 所需要的步骤数：</p>\n\n<ul>\n\t<li>\n\t<p>如果当前数字为偶数，则将其除以 2 。</p>\n\t</li>\n\t<li>\n\t<p>如果当前数字为奇数，则将其加上 1 。</p>\n\t</li>\n</ul>\n\n<p>题目保证你总是可以按上述规则将测试用例变为 1 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>s = "1101"\n<strong>输出：</strong>6\n<strong>解释：</strong>"1101" 表示十进制数 13 。\nStep 1) 13 是奇数，加 1 得到 14 \nStep 2) 14 是偶数，除 2 得到 7\nStep 3) 7 是奇数，加 1 得到 8\nStep 4) 8 是偶数，除 2 得到 4 \nStep 5) 4 是偶数，除 2 得到 2 \nStep 6) 2 是偶数，除 2 得到 1 \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>s = "10"\n<strong>输出：</strong>1\n<strong>解释：</strong>"10" 表示十进制数 2 。\nStep 1) 2 是偶数，除 2 得到 1 \n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>s = "1"\n<strong>输出：</strong>0\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 500</code></li>\n\t<li><code>s</code> 由字符 <code>'0'</code> 或 <code>'1'</code> 组成。</li>\n\t<li><code>s[0] == '1'</code></li>\n</ul>\n",
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"Read the string from right to left, if the string ends in '0' then the number is even otherwise it is odd.",
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"Simulate the steps described in the binary string."
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