leetcode-problemset/leetcode-cn/originData/number-of-provinces.json

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            "title": "Number of Provinces",
            "titleSlug": "number-of-provinces",
            "content": "<p>There are <code>n</code> cities. Some of them are connected, while some are not. If city <code>a</code> is connected directly with city <code>b</code>, and city <code>b</code> is connected directly with city <code>c</code>, then city <code>a</code> is connected indirectly with city <code>c</code>.</p>\n\n<p>A <strong>province</strong> is a group of directly or indirectly connected cities and no other cities outside of the group.</p>\n\n<p>You are given an <code>n x n</code> matrix <code>isConnected</code> where <code>isConnected[i][j] = 1</code> if the <code>i<sup>th</sup></code> city and the <code>j<sup>th</sup></code> city are directly connected, and <code>isConnected[i][j] = 0</code> otherwise.</p>\n\n<p>Return <em>the total number of <strong>provinces</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/graph1.jpg\" style=\"width: 222px; height: 142px;\" />\n<pre>\n<strong>Input:</strong> isConnected = [[1,1,0],[1,1,0],[0,0,1]]\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/graph2.jpg\" style=\"width: 222px; height: 142px;\" />\n<pre>\n<strong>Input:</strong> isConnected = [[1,0,0],[0,1,0],[0,0,1]]\n<strong>Output:</strong> 3\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 200</code></li>\n\t<li><code>n == isConnected.length</code></li>\n\t<li><code>n == isConnected[i].length</code></li>\n\t<li><code>isConnected[i][j]</code> is <code>1</code> or <code>0</code>.</li>\n\t<li><code>isConnected[i][i] == 1</code></li>\n\t<li><code>isConnected[i][j] == isConnected[j][i]</code></li>\n</ul>\n",
            "translatedTitle": "省份数量",
            "translatedContent": "<div class=\"original__bRMd\">\n<div>\n<p>有 <code>n</code> 个城市，其中一些彼此相连，另一些没有相连。如果城市 <code>a</code> 与城市 <code>b</code> 直接相连，且城市 <code>b</code> 与城市 <code>c</code> 直接相连，那么城市 <code>a</code> 与城市 <code>c</code> 间接相连。</p>\n\n<p><strong>省份</strong> 是一组直接或间接相连的城市，组内不含其他没有相连的城市。</p>\n\n<p>给你一个 <code>n x n</code> 的矩阵 <code>isConnected</code> ，其中 <code>isConnected[i][j] = 1</code> 表示第 <code>i</code> 个城市和第 <code>j</code> 个城市直接相连，而 <code>isConnected[i][j] = 0</code> 表示二者不直接相连。</p>\n\n<p>返回矩阵中 <strong>省份</strong> 的数量。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/graph1.jpg\" style=\"width: 222px; height: 142px;\" />\n<pre>\n<strong>输入：</strong>isConnected = [[1,1,0],[1,1,0],[0,0,1]]\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/12/24/graph2.jpg\" style=\"width: 222px; height: 142px;\" />\n<pre>\n<strong>输入：</strong>isConnected = [[1,0,0],[0,1,0],[0,0,1]]\n<strong>输出：</strong>3\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 200</code></li>\n\t<li><code>n == isConnected.length</code></li>\n\t<li><code>n == isConnected[i].length</code></li>\n\t<li><code>isConnected[i][j]</code> 为 <code>1</code> 或 <code>0</code></li>\n\t<li><code>isConnected[i][i] == 1</code></li>\n\t<li><code>isConnected[i][j] == isConnected[j][i]</code></li>\n</ul>\n</div>\n</div>\n",
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