leetcode-problemset/leetcode-cn/originData/minimum-path-sum.json

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            "title": "Minimum Path Sum",
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            "content": "<p>Given a <code>m x n</code> <code>grid</code> filled with non-negative numbers, find a path from top left to bottom right, which minimizes the sum of all numbers along its path.</p>\n\n<p><strong>Note:</strong> You can only move either down or right at any point in time.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/05/minpath.jpg\" style=\"width: 242px; height: 242px;\" />\n<pre>\n<strong>Input:</strong> grid = [[1,3,1],[1,5,1],[4,2,1]]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> Because the path 1 &rarr; 3 &rarr; 1 &rarr; 1 &rarr; 1 minimizes the sum.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> grid = [[1,2,3],[4,5,6]]\n<strong>Output:</strong> 12\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 200</code></li>\n\t<li><code>0 &lt;= grid[i][j] &lt;= 200</code></li>\n</ul>\n",
            "translatedTitle": "最小路径和",
            "translatedContent": "<p>给定一个包含非负整数的 <code><em>m</em>&nbsp;x&nbsp;<em>n</em></code>&nbsp;网格&nbsp;<code>grid</code> ，请找出一条从左上角到右下角的路径，使得路径上的数字总和为最小。</p>\n\n<p><strong>说明：</strong>每次只能向下或者向右移动一步。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/05/minpath.jpg\" style=\"width: 242px; height: 242px;\" />\n<pre>\n<strong>输入：</strong>grid = [[1,3,1],[1,5,1],[4,2,1]]\n<strong>输出：</strong>7\n<strong>解释：</strong>因为路径 1→3→1→1→1 的总和最小。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>grid = [[1,2,3],[4,5,6]]\n<strong>输出：</strong>12\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 200</code></li>\n\t<li><code>0 &lt;= grid[i][j] &lt;= 200</code></li>\n</ul>\n",
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