leetcode-problemset/leetcode-cn/originData/minimum-operations-to-make-the-array-increasing.json

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            "title": "Minimum Operations to Make the Array Increasing",
            "titleSlug": "minimum-operations-to-make-the-array-increasing",
            "content": "<p>You are given an integer array <code>nums</code> (<strong>0-indexed</strong>). In one operation, you can choose an element of the array and increment it by <code>1</code>.</p>\r\n\r\n<ul>\r\n\t<li>For example, if <code>nums = [1,2,3]</code>, you can choose to increment <code>nums[1]</code> to make <code>nums = [1,<u><b>3</b></u>,3]</code>.</li>\r\n</ul>\r\n\r\n<p>Return <em>the <strong>minimum</strong> number of operations needed to make</em> <code>nums</code> <em><strong>strictly</strong> <strong>increasing</strong>.</em></p>\r\n\r\n<p>An array <code>nums</code> is <strong>strictly increasing</strong> if <code>nums[i] &lt; nums[i+1]</code> for all <code>0 &lt;= i &lt; nums.length - 1</code>. An array of length <code>1</code> is trivially strictly increasing.</p>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong class=\"example\">Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [1,1,1]\r\n<strong>Output:</strong> 3\r\n<strong>Explanation:</strong> You can do the following operations:\r\n1) Increment nums[2], so nums becomes [1,1,<u><strong>2</strong></u>].\r\n2) Increment nums[1], so nums becomes [1,<u><strong>2</strong></u>,2].\r\n3) Increment nums[2], so nums becomes [1,2,<u><strong>3</strong></u>].\r\n</pre>\r\n\r\n<p><strong class=\"example\">Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [1,5,2,4,1]\r\n<strong>Output:</strong> 14\r\n</pre>\r\n\r\n<p><strong class=\"example\">Example 3:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> nums = [8]\r\n<strong>Output:</strong> 0\r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Constraints:</strong></p>\r\n\r\n<ul>\r\n\t<li><code>1 &lt;= nums.length &lt;= 5000</code></li>\r\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\r\n</ul>",
            "translatedTitle": "最少操作使数组递增",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> （<strong>下标从 0 开始</strong>）。每一次操作中，你可以选择数组中一个元素，并将它增加 <code>1</code> 。</p>\n\n<ul>\n\t<li>比方说，如果 <code>nums = [1,2,3]</code> ，你可以选择增加 <code>nums[1]</code> 得到 <code>nums = [1,<b>3</b>,3]</code> 。</li>\n</ul>\n\n<p>请你返回使 <code>nums</code> <strong>严格递增</strong> 的 <strong>最少</strong> 操作次数。</p>\n\n<p>我们称数组 <code>nums</code> 是 <strong>严格递增的</strong> ，当它满足对于所有的 <code>0 &lt;= i &lt; nums.length - 1</code> 都有 <code>nums[i] &lt; nums[i+1]</code> 。一个长度为 <code>1</code> 的数组是严格递增的一种特殊情况。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [1,1,1]\n<b>输出：</b>3\n<b>解释：</b>你可以进行如下操作：\n1) 增加 nums[2] ，数组变为 [1,1,<strong>2</strong>] 。\n2) 增加 nums[1] ，数组变为 [1,<strong>2</strong>,2] 。\n3) 增加 nums[2] ，数组变为 [1,2,<strong>3</strong>] 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [1,5,2,4,1]\n<b>输出：</b>14\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><b>输入：</b>nums = [8]\n<b>输出：</b>0\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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                "nums[i+1] must be at least equal to nums[i] + 1.",
                "Think greedily. You don't have to increase nums[i+1] beyond nums[i]+1.",
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