leetcode-problemset/leetcode-cn/originData/maximum-matrix-sum.json

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            "title": "Maximum Matrix Sum",
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            "content": "<p>You are given an <code>n x n</code> integer <code>matrix</code>. You can do the following operation <strong>any</strong> number of times:</p>\n\n<ul>\n\t<li>Choose any two <strong>adjacent</strong> elements of <code>matrix</code> and <strong>multiply</strong> each of them by <code>-1</code>.</li>\n</ul>\n\n<p>Two elements are considered <strong>adjacent</strong> if and only if they share a <strong>border</strong>.</p>\n\n<p>Your goal is to <strong>maximize</strong> the summation of the matrix&#39;s elements. Return <em>the <strong>maximum</strong> sum of the matrix&#39;s elements using the operation mentioned above.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/16/pc79-q2ex1.png\" style=\"width: 401px; height: 81px;\" />\n<pre>\n<strong>Input:</strong> matrix = [[1,-1],[-1,1]]\n<strong>Output:</strong> 4\n<b>Explanation:</b> We can follow the following steps to reach sum equals 4:\n- Multiply the 2 elements in the first row by -1.\n- Multiply the 2 elements in the first column by -1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/16/pc79-q2ex2.png\" style=\"width: 321px; height: 121px;\" />\n<pre>\n<strong>Input:</strong> matrix = [[1,2,3],[-1,-2,-3],[1,2,3]]\n<strong>Output:</strong> 16\n<b>Explanation:</b> We can follow the following step to reach sum equals 16:\n- Multiply the 2 last elements in the second row by -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == matrix.length == matrix[i].length</code></li>\n\t<li><code>2 &lt;= n &lt;= 250</code></li>\n\t<li><code>-10<sup>5</sup> &lt;= matrix[i][j] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "最大方阵和",
            "translatedContent": "<p>给你一个&nbsp;<code>n x n</code>&nbsp;的整数方阵&nbsp;<code>matrix</code>&nbsp;。你可以执行以下操作&nbsp;<strong>任意次</strong>&nbsp;：</p>\n\n<ul>\n\t<li>选择&nbsp;<code>matrix</code>&nbsp;中&nbsp;<strong>相邻</strong>&nbsp;两个元素，并将它们都 <strong>乘以</strong>&nbsp;<code>-1</code>&nbsp;。</li>\n</ul>\n\n<p>如果两个元素有 <strong>公共边</strong>&nbsp;，那么它们就是 <strong>相邻</strong>&nbsp;的。</p>\n\n<p>你的目的是 <strong>最大化</strong>&nbsp;方阵元素的和。请你在执行以上操作之后，返回方阵的&nbsp;<strong>最大</strong>&nbsp;和。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/16/pc79-q2ex1.png\" style=\"width: 401px; height: 81px;\">\n<pre><b>输入：</b>matrix = [[1,-1],[-1,1]]\n<b>输出：</b>4\n<b>解释：</b>我们可以执行以下操作使和等于 4 ：\n- 将第一行的 2 个元素乘以 -1 。\n- 将第一列的 2 个元素乘以 -1 。\n</pre>\n\n<p><strong>示例&nbsp;2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/16/pc79-q2ex2.png\" style=\"width: 321px; height: 121px;\">\n<pre><b>输入：</b>matrix = [[1,2,3],[-1,-2,-3],[1,2,3]]\n<b>输出：</b>16\n<b>解释：</b>我们可以执行以下操作使和等于 16 ：\n- 将第二行的最后 2 个元素乘以 -1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == matrix.length == matrix[i].length</code></li>\n\t<li><code>2 &lt;= n &lt;= 250</code></li>\n\t<li><code>-10<sup>5</sup> &lt;= matrix[i][j] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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