mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
189 lines
21 KiB
JSON
189 lines
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JSON
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"title": "Maximize Greatness of an Array",
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"content": "<p>You are given a 0-indexed integer array <code>nums</code>. You are allowed to permute <code>nums</code> into a new array <code>perm</code> of your choosing.</p>\n\n<p>We define the <strong>greatness</strong> of <code>nums</code> be the number of indices <code>0 <= i < nums.length</code> for which <code>perm[i] > nums[i]</code>.</p>\n\n<p>Return <em>the <strong>maximum</strong> possible greatness you can achieve after permuting</em> <code>nums</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,5,2,1,3,1]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> One of the optimal rearrangements is perm = [2,5,1,3,3,1,1].\nAt indices = 0, 1, 3, and 4, perm[i] > nums[i]. Hence, we return 4.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can prove the optimal perm is [2,3,4,1].\nAt indices = 0, 1, and 2, perm[i] > nums[i]. Hence, we return 3.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedContent": "<p>给你一个下标从 0 开始的整数数组 <code>nums</code> 。你需要将 <code>nums</code> 重新排列成一个新的数组 <code>perm</code> 。</p>\n\n<p>定义 <code>nums</code> 的 <strong>伟大值</strong> 为满足 <code>0 <= i < nums.length</code> 且 <code>perm[i] > nums[i]</code> 的下标数目。</p>\n\n<p>请你返回重新排列 <code>nums</code> 后的 <strong>最大</strong> 伟大值。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [1,3,5,2,1,3,1]\n<b>输出：</b>4\n<b>解释：</b>一个最优安排方案为 perm = [2,5,1,3,3,1,1] 。\n在下标为 0, 1, 3 和 4 处，都有 perm[i] > nums[i] 。因此我们返回 4 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [1,2,3,4]\n<b>输出：</b>3\n<b>解释：</b>最优排列为 [2,3,4,1] 。\n在下标为 0, 1 和 2 处，都有 perm[i] > nums[i] 。因此我们返回 3 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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