leetcode-problemset/leetcode-cn/originData/make-string-a-subsequence-using-cyclic-increments.json

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        "question": {
            "questionId": "3018",
            "questionFrontendId": "2825",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2393665,
            "title": "Make String a Subsequence Using Cyclic Increments",
            "titleSlug": "make-string-a-subsequence-using-cyclic-increments",
            "content": "<p>You are given two <strong>0-indexed</strong> strings <code>str1</code> and <code>str2</code>.</p>\n\n<p>In an operation, you select a <strong>set</strong> of indices in <code>str1</code>, and for each index <code>i</code> in the set, increment <code>str1[i]</code> to the next character <strong>cyclically</strong>. That is <code>&#39;a&#39;</code> becomes <code>&#39;b&#39;</code>, <code>&#39;b&#39;</code> becomes <code>&#39;c&#39;</code>, and so on, and <code>&#39;z&#39;</code> becomes <code>&#39;a&#39;</code>.</p>\n\n<p>Return <code>true</code> <em>if it is possible to make </em><code>str2</code> <em>a subsequence of </em><code>str1</code> <em>by performing the operation <strong>at most once</strong></em>, <em>and</em> <code>false</code> <em>otherwise</em>.</p>\n\n<p><strong>Note:</strong> A subsequence of a string is a new string that is formed from the original string by deleting some (possibly none) of the characters without disturbing the relative positions of the remaining characters.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;abc&quot;, str2 = &quot;ad&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Select index 2 in str1.\nIncrement str1[2] to become &#39;d&#39;. \nHence, str1 becomes &quot;abd&quot; and str2 is now a subsequence. Therefore, true is returned.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;zc&quot;, str2 = &quot;ad&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Select indices 0 and 1 in str1. \nIncrement str1[0] to become &#39;a&#39;. \nIncrement str1[1] to become &#39;d&#39;. \nHence, str1 becomes &quot;ad&quot; and str2 is now a subsequence. Therefore, true is returned.</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> str1 = &quot;ab&quot;, str2 = &quot;d&quot;\n<strong>Output:</strong> false\n<strong>Explanation:</strong> In this example, it can be shown that it is impossible to make str2 a subsequence of str1 using the operation at most once. \nTherefore, false is returned.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= str1.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= str2.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>str1</code> and <code>str2</code> consist of only lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "循环增长使字符串子序列等于另一个字符串",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的字符串&nbsp;<code>str1</code> 和&nbsp;<code>str2</code>&nbsp;。</p>\n\n<p>一次操作中，你选择&nbsp;<code>str1</code>&nbsp;中的若干下标。对于选中的每一个下标&nbsp;<code>i</code>&nbsp;，你将&nbsp;<code>str1[i]</code>&nbsp;<strong>循环</strong>&nbsp;递增，变成下一个字符。也就是说&nbsp;<code>'a'</code>&nbsp;变成&nbsp;<code>'b'</code>&nbsp;，<code>'b'</code> 变成&nbsp;<code>'c'</code>&nbsp;，以此类推，<code>'z'</code> 变成&nbsp;<code>'a'</code>&nbsp;。</p>\n\n<p>如果执行以上操作 <strong>至多一次</strong>&nbsp;，可以让 <code>str2</code>&nbsp;成为 <code>str1</code>&nbsp;的子序列，请你返回 <code>true</code>&nbsp;，否则返回 <code>false</code>&nbsp;。</p>\n\n<p><b>注意：</b>一个字符串的子序列指的是从原字符串中删除一些（可以一个字符也不删）字符后，剩下字符按照原本先后顺序组成的新字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>str1 = \"abc\", str2 = \"ad\"\n<b>输出：</b>true\n<b>解释：</b>选择 str1 中的下标 2 。\n将 str1[2] 循环递增，得到 'd' 。\n因此，str1 变成 \"abd\" 且 str2 现在是一个子序列。所以返回 true 。</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>str1 = \"zc\", str2 = \"ad\"\n<b>输出：</b>true\n<b>解释：</b>选择 str1 中的下标 0 和 1 。\n将 str1[0] 循环递增得到 'a' 。\n将 str1[1] 循环递增得到 'd' 。\n因此，str1 变成 \"ad\" 且 str2 现在是一个子序列。所以返回 true 。</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>str1 = \"ab\", str2 = \"d\"\n<b>输出：</b>false\n<b>解释：</b>这个例子中，没法在执行一次操作的前提下，将 str2 变为 str1 的子序列。\n所以返回 false 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= str1.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= str2.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>str1</code>&nbsp;和&nbsp;<code>str2</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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            "hints": [
                "<div class=\"_1l1MA\">Consider the indices we will increment separately.</div>",
                "<div class=\"_1l1MA\">We can maintain two pointers: pointer <code>i</code> for <code>str1</code> and pointer <code>j</code> for <code>str2</code>, while ensuring they remain within the bounds of the strings.</div>",
                "<div class=\"_1l1MA\">If both <code>str1[i]</code> and <code>str2[j]</code> match, or if incrementing <code>str1[i]</code> matches <code>str2[j]</code>, we increase both pointers; otherwise, we increment only pointer <code>i</code>.</div>",
                "<div class=\"_1l1MA\">It is possible to make <code>str2</code> a subsequence of <code>str1</code> if <code>j</code> is at the end of <code>str2</code>, after we can no longer find a match.</div>"
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