leetcode-problemset/leetcode-cn/originData/longest-duplicate-substring.json

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        "question": {
            "questionId": "1122",
            "questionFrontendId": "1044",
            "categoryTitle": "Algorithms",
            "boundTopicId": 4578,
            "title": "Longest Duplicate Substring",
            "titleSlug": "longest-duplicate-substring",
            "content": "<p>Given a string <code>s</code>, consider all <em>duplicated substrings</em>: (contiguous) substrings of s that occur 2 or more times.&nbsp;The occurrences&nbsp;may overlap.</p>\n\n<p>Return <strong>any</strong> duplicated&nbsp;substring that has the longest possible length.&nbsp;If <code>s</code> does not have a duplicated substring, the answer is <code>&quot;&quot;</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<pre><strong>Input:</strong> s = \"banana\"\n<strong>Output:</strong> \"ana\"\n</pre><p><strong class=\"example\">Example 2:</strong></p>\n<pre><strong>Input:</strong> s = \"abcd\"\n<strong>Output:</strong> \"\"\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= s.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "最长重复子串",
            "translatedContent": "<p>给你一个字符串 <code>s</code> ，考虑其所有 <em>重复子串</em> ：即&nbsp;<code>s</code> 的（连续）子串，在 <code>s</code> 中出现 2 次或更多次。这些出现之间可能存在重叠。</p>\n\n<p>返回 <strong>任意一个</strong> 可能具有最长长度的重复子串。如果 <code>s</code> 不含重复子串，那么答案为 <code>\"\"</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"banana\"\n<strong>输出：</strong>\"ana\"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"abcd\"\n<strong>输出：</strong>\"\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= s.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>s</code> 由小写英文字母组成</li>\n</ul>\n",
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            "difficulty": "Hard",
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                    "code": "class Solution {\npublic:\n    string longestDupSubstring(string s) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def longestDupSubstring(self, s):\n        \"\"\"\n        :type s: str\n        :rtype: str\n        \"\"\"",
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                    "code": "char* longestDupSubstring(char* s) {\n    \n}",
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                    "code": "public class Solution {\n    public string LongestDupSubstring(string s) {\n\n    }\n}",
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                    "lang": "JavaScript",
                    "langSlug": "javascript",
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                    "code": "function longestDupSubstring(s: string): string {\n    \n};",
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                    "lang": "PHP",
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                    "lang": "Go",
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                    "code": "func longestDupSubstring(s string) string {\n\n}",
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                    "lang": "Ruby",
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                    "code": "# @param {String} s\n# @return {String}\ndef longest_dup_substring(s)\n\nend",
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                    "langSlug": "scala",
                    "code": "object Solution {\n    def longestDupSubstring(s: String): String = {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
                },
                {
                    "lang": "Rust",
                    "langSlug": "rust",
                    "code": "impl Solution {\n    pub fn longest_dup_substring(s: String) -> String {\n\n    }\n}",
                    "__typename": "CodeSnippetNode"
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                {
                    "lang": "Racket",
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                    "code": "(define/contract (longest-dup-substring s)\n  (-> string? string?)\n  )",
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                    "lang": "Erlang",
                    "langSlug": "erlang",
                    "code": "-spec longest_dup_substring(S :: unicode:unicode_binary()) -> unicode:unicode_binary().\nlongest_dup_substring(S) ->\n  .",
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                    "lang": "Elixir",
                    "langSlug": "elixir",
                    "code": "defmodule Solution do\n  @spec longest_dup_substring(s :: String.t) :: String.t\n  def longest_dup_substring(s) do\n    \n  end\nend",
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                }
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            "hints": [
                "Binary search for the length of the answer.  (If there's an answer of length 10, then there are answers of length 9, 8, 7, ...)",
                "To check whether an answer of length K exists, we can use Rabin-Karp 's algorithm."
            ],
            "solution": null,
            "status": null,
            "sampleTestCase": "\"banana\"",
            "metaData": "{\n  \"name\": \"longestDupSubstring\",\n  \"params\": [\n    {\n      \"name\": \"s\",\n      \"type\": \"string\"\n    }\n  ],\n  \"return\": {\n    \"type\": \"string\"\n  }\n}",
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