mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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150 lines
24 KiB
JSON
150 lines
24 KiB
JSON
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"questionId": "142",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1351,
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"title": "Linked List Cycle II",
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"titleSlug": "linked-list-cycle-ii",
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"content": "<p>Given the <code>head</code> of a linked list, return <em>the node where the cycle begins. If there is no cycle, return </em><code>null</code>.</p>\n\n<p>There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the <code>next</code> pointer. Internally, <code>pos</code> is used to denote the index of the node that tail's <code>next</code> pointer is connected to (<strong>0-indexed</strong>). It is <code>-1</code> if there is no cycle. <strong>Note that</strong> <code>pos</code> <strong>is not passed as a parameter</strong>.</p>\n\n<p><strong>Do not modify</strong> the linked list.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist.png\" style=\"height: 145px; width: 450px;\" />\n<pre>\n<strong>Input:</strong> head = [3,2,0,-4], pos = 1\n<strong>Output:</strong> tail connects to node index 1\n<strong>Explanation:</strong> There is a cycle in the linked list, where tail connects to the second node.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist_test2.png\" style=\"height: 105px; width: 201px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2], pos = 0\n<strong>Output:</strong> tail connects to node index 0\n<strong>Explanation:</strong> There is a cycle in the linked list, where tail connects to the first node.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist_test3.png\" style=\"height: 65px; width: 65px;\" />\n<pre>\n<strong>Input:</strong> head = [1], pos = -1\n<strong>Output:</strong> no cycle\n<strong>Explanation:</strong> There is no cycle in the linked list.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of the nodes in the list is in the range <code>[0, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n\t<li><code>pos</code> is <code>-1</code> or a <strong>valid index</strong> in the linked-list.</li>\n</ul>\n\n<p> </p>\n<p><strong>Follow up:</strong> Can you solve it using <code>O(1)</code> (i.e. constant) memory?</p>\n",
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"translatedTitle": "环形链表 II",
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"translatedContent": "<p>给定一个链表的头节点 <code>head</code> ,返回链表开始入环的第一个节点。 <em>如果链表无环,则返回 <code>null</code>。</em></p>\n\n<p>如果链表中有某个节点,可以通过连续跟踪 <code>next</code> 指针再次到达,则链表中存在环。 为了表示给定链表中的环,评测系统内部使用整数 <code>pos</code> 来表示链表尾连接到链表中的位置(<strong>索引从 0 开始</strong>)。如果 <code>pos</code> 是 <code>-1</code>,则在该链表中没有环。<strong>注意:<code>pos</code> 不作为参数进行传递</strong>,仅仅是为了标识链表的实际情况。</p>\n\n<p><strong>不允许修改 </strong>链表。</p>\n\n<ul>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist.png\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [3,2,0,-4], pos = 1\n<strong>输出:</strong>返回索引为 1 的链表节点\n<strong>解释:</strong>链表中有一个环,其尾部连接到第二个节点。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/07/circularlinkedlist_test2.png\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [1,2], pos = 0\n<strong>输出:</strong>返回索引为 0 的链表节点\n<strong>解释:</strong>链表中有一个环,其尾部连接到第一个节点。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2018/12/07/circularlinkedlist_test3.png\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [1], pos = -1\n<strong>输出:</strong>返回 null\n<strong>解释:</strong>链表中没有环。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>链表中节点的数目范围在范围 <code>[0, 10<sup>4</sup>]</code> 内</li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n\t<li><code>pos</code> 的值为 <code>-1</code> 或者链表中的一个有效索引</li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶:</strong>你是否可以使用 <code>O(1)</code> 空间解决此题?</p>\n",
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/tree\\/fb4fdb984834421279aeb081df7af624d17c2a03\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.3.0<\\/a> \\u548c <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/e63563025a5a805aa16928cb53bcd517bfea9230\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.1<\\/a>\\u3002<\\/p>\"]}",
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