leetcode-problemset/leetcode-cn/originData/kTOapQ.json

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    "data": {
        "question": {
            "questionId": "1000316",
            "questionFrontendId": "LCR 055",
            "categoryTitle": "Algorithms",
            "boundTopicId": 910310,
            "title": "二叉搜索树迭代器",
            "titleSlug": "kTOapQ",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
            "translatedTitle": "二叉搜索树迭代器",
            "translatedContent": "<p>实现一个二叉搜索树迭代器类<code>BSTIterator</code> ，表示一个按中序遍历二叉搜索树（BST）的迭代器：</p>\n\n<div class=\"original__bRMd\">\n<div>\n<ul>\n\t<li><code>BSTIterator(TreeNode root)</code> 初始化 <code>BSTIterator</code> 类的一个对象。BST 的根节点 <code>root</code> 会作为构造函数的一部分给出。指针应初始化为一个不存在于 BST 中的数字，且该数字小于 BST 中的任何元素。</li>\n\t<li><code>boolean hasNext()</code> 如果向指针右侧遍历存在数字，则返回 <code>true</code> ；否则返回 <code>false</code> 。</li>\n\t<li><code>int next()</code>将指针向右移动，然后返回指针处的数字。</li>\n</ul>\n\n<p>注意，指针初始化为一个不存在于 BST 中的数字，所以对 <code>next()</code> 的首次调用将返回 BST 中的最小元素。</p>\n</div>\n</div>\n\n<p>可以假设&nbsp;<code>next()</code>&nbsp;调用总是有效的，也就是说，当调用 <code>next()</code>&nbsp;时，BST 的中序遍历中至少存在一个下一个数字。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2018/12/25/bst-tree.png\" style=\"width: 189px; height: 178px;\" /></p>\n\n<pre>\n<strong>输入</strong>\ninputs = [&quot;BSTIterator&quot;, &quot;next&quot;, &quot;next&quot;, &quot;hasNext&quot;, &quot;next&quot;, &quot;hasNext&quot;, &quot;next&quot;, &quot;hasNext&quot;, &quot;next&quot;, &quot;hasNext&quot;]\ninputs = [[[7, 3, 15, null, null, 9, 20]], [], [], [], [], [], [], [], [], []]\n<strong>输出</strong>\n[null, 3, 7, true, 9, true, 15, true, 20, false]\n\n<strong>解释</strong>\nBSTIterator bSTIterator = new BSTIterator([7, 3, 15, null, null, 9, 20]);\nbSTIterator.next();    // 返回 3\nbSTIterator.next();    // 返回 7\nbSTIterator.hasNext(); // 返回 True\nbSTIterator.next();    // 返回 9\nbSTIterator.hasNext(); // 返回 True\nbSTIterator.next();    // 返回 15\nbSTIterator.hasNext(); // 返回 True\nbSTIterator.next();    // 返回 20\nbSTIterator.hasNext(); // 返回 False\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点的数目在范围 <code>[1, 10<sup>5</sup>]</code> 内</li>\n\t<li><code>0 &lt;= Node.val &lt;= 10<sup>6</sup></code></li>\n\t<li>最多调用 <code>10<sup>5</sup></code> 次 <code>hasNext</code> 和 <code>next</code> 操作</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong></p>\n\n<ul>\n\t<li>你可以设计一个满足下述条件的解决方案吗？<code>next()</code> 和 <code>hasNext()</code> 操作均摊时间复杂度为 <code>O(1)</code> ，并使用 <code>O(h)</code> 内存。其中 <code>h</code> 是树的高度。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 173&nbsp;题相同：&nbsp;<a href=\"https://leetcode-cn.com/problems/binary-search-tree-iterator/\">https://leetcode-cn.com/problems/binary-search-tree-iterator/</a></p>\n",
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                    "lang": "C++",
                    "langSlug": "cpp",
                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     TreeNode *left;\n *     TreeNode *right;\n *     TreeNode() : val(0), left(nullptr), right(nullptr) {}\n *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass BSTIterator {\npublic:\n    BSTIterator(TreeNode* root) {\n\n    }\n    \n    int next() {\n\n    }\n    \n    bool hasNext() {\n\n    }\n};\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * BSTIterator* obj = new BSTIterator(root);\n * int param_1 = obj->next();\n * bool param_2 = obj->hasNext();\n */",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     int val;\n *     TreeNode left;\n *     TreeNode right;\n *     TreeNode() {}\n *     TreeNode(int val) { this.val = val; }\n *     TreeNode(int val, TreeNode left, TreeNode right) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\nclass BSTIterator {\n\n    public BSTIterator(TreeNode root) {\n\n    }\n    \n    public int next() {\n\n    }\n    \n    public boolean hasNext() {\n\n    }\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * BSTIterator obj = new BSTIterator(root);\n * int param_1 = obj.next();\n * boolean param_2 = obj.hasNext();\n */",
                    "__typename": "CodeSnippetNode"
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                    "lang": "Python",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode(object):\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass BSTIterator(object):\n\n    def __init__(self, root):\n        \"\"\"\n        :type root: TreeNode\n        \"\"\"\n\n\n    def next(self):\n        \"\"\"\n        :rtype: int\n        \"\"\"\n\n\n    def hasNext(self):\n        \"\"\"\n        :rtype: bool\n        \"\"\"\n\n\n\n# Your BSTIterator object will be instantiated and called as such:\n# obj = BSTIterator(root)\n# param_1 = obj.next()\n# param_2 = obj.hasNext()",
                    "__typename": "CodeSnippetNode"
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                    "lang": "Python3",
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                    "code": "# Definition for a binary tree node.\n# class TreeNode:\n#     def __init__(self, val=0, left=None, right=None):\n#         self.val = val\n#         self.left = left\n#         self.right = right\nclass BSTIterator:\n\n    def __init__(self, root: TreeNode):\n\n\n    def next(self) -> int:\n\n\n    def hasNext(self) -> bool:\n\n\n\n# Your BSTIterator object will be instantiated and called as such:\n# obj = BSTIterator(root)\n# param_1 = obj.next()\n# param_2 = obj.hasNext()",
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                    "lang": "C",
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                    "code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n *     int val;\n *     struct TreeNode *left;\n *     struct TreeNode *right;\n * };\n */\n\n\n\ntypedef struct {\n\n} BSTIterator;\n\n\nBSTIterator* bSTIteratorCreate(struct TreeNode* root) {\n\n}\n\nint bSTIteratorNext(BSTIterator* obj) {\n\n}\n\nbool bSTIteratorHasNext(BSTIterator* obj) {\n\n}\n\nvoid bSTIteratorFree(BSTIterator* obj) {\n\n}\n\n/**\n * Your BSTIterator struct will be instantiated and called as such:\n * BSTIterator* obj = bSTIteratorCreate(root);\n * int param_1 = bSTIteratorNext(obj);\n \n * bool param_2 = bSTIteratorHasNext(obj);\n \n * bSTIteratorFree(obj);\n*/",
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                    "lang": "C#",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public int val;\n *     public TreeNode left;\n *     public TreeNode right;\n *     public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n *         this.val = val;\n *         this.left = left;\n *         this.right = right;\n *     }\n * }\n */\npublic class BSTIterator {\n\n    public BSTIterator(TreeNode root) {\n\n    }\n    \n    public int Next() {\n\n    }\n    \n    public bool HasNext() {\n\n    }\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * BSTIterator obj = new BSTIterator(root);\n * int param_1 = obj.Next();\n * bool param_2 = obj.HasNext();\n */",
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                    "lang": "JavaScript",
                    "langSlug": "javascript",
                    "code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.left = (left===undefined ? null : left)\n *     this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n */\nvar BSTIterator = function(root) {\n\n};\n\n/**\n * @return {number}\n */\nBSTIterator.prototype.next = function() {\n\n};\n\n/**\n * @return {boolean}\n */\nBSTIterator.prototype.hasNext = function() {\n\n};\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * var obj = new BSTIterator(root)\n * var param_1 = obj.next()\n * var param_2 = obj.hasNext()\n */",
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                    "lang": "TypeScript",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     val: number\n *     left: TreeNode | null\n *     right: TreeNode | null\n *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.left = (left===undefined ? null : left)\n *         this.right = (right===undefined ? null : right)\n *     }\n * }\n */\n\nclass BSTIterator {\n    constructor(root: TreeNode | null) {\n\n    }\n\n    next(): number {\n\n    }\n\n    hasNext(): boolean {\n\n    }\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * var obj = new BSTIterator(root)\n * var param_1 = obj.next()\n * var param_2 = obj.hasNext()\n */",
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                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n *     public $val = null;\n *     public $left = null;\n *     public $right = null;\n *     function __construct($val = 0, $left = null, $right = null) {\n *         $this->val = $val;\n *         $this->left = $left;\n *         $this->right = $right;\n *     }\n * }\n */\nclass BSTIterator {\n    /**\n     * @param TreeNode $root\n     */\n    function __construct($root) {\n\n    }\n\n    /**\n     * @return Integer\n     */\n    function next() {\n\n    }\n\n    /**\n     * @return Boolean\n     */\n    function hasNext() {\n\n    }\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * $obj = BSTIterator($root);\n * $ret_1 = $obj->next();\n * $ret_2 = $obj->hasNext();\n */",
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                    "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n *     public var val: Int\n *     public var left: TreeNode?\n *     public var right: TreeNode?\n *     public init() { self.val = 0; self.left = nil; self.right = nil; }\n *     public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n *     public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n *         self.val = val\n *         self.left = left\n *         self.right = right\n *     }\n * }\n */\n\nclass BSTIterator {\n\n    init(_ root: TreeNode?) {\n\n    }\n    \n    func next() -> Int {\n\n    }\n    \n    func hasNext() -> Bool {\n\n    }\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * let obj = BSTIterator(root)\n * let ret_1: Int = obj.next()\n * let ret_2: Bool = obj.hasNext()\n */",
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                    "lang": "Kotlin",
                    "langSlug": "kotlin",
                    "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n *     var left: TreeNode? = null\n *     var right: TreeNode? = null\n * }\n */\nclass BSTIterator(root: TreeNode?) {\n\n    fun next(): Int {\n\n    }\n\n    fun hasNext(): Boolean {\n\n    }\n\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * var obj = BSTIterator(root)\n * var param_1 = obj.next()\n * var param_2 = obj.hasNext()\n */",
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                    "lang": "Go",
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                    "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n *     Val int\n *     Left *TreeNode\n *     Right *TreeNode\n * }\n */\ntype BSTIterator struct {\n\n}\n\n\nfunc Constructor(root *TreeNode) BSTIterator {\n\n}\n\n\nfunc (this *BSTIterator) Next() int {\n\n}\n\n\nfunc (this *BSTIterator) HasNext() bool {\n\n}\n\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * obj := Constructor(root);\n * param_1 := obj.Next();\n * param_2 := obj.HasNext();\n */",
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                {
                    "lang": "Ruby",
                    "langSlug": "ruby",
                    "code": "# Definition for a binary tree node.\n# class TreeNode\n#     attr_accessor :val, :left, :right\n#     def initialize(val = 0, left = nil, right = nil)\n#         @val = val\n#         @left = left\n#         @right = right\n#     end\n# end\nclass BSTIterator\n\n=begin\n    :type root: TreeNode\n=end\n    def initialize(root)\n\n    end\n\n\n=begin\n    :rtype: Integer\n=end\n    def next()\n\n    end\n\n\n=begin\n    :rtype: Boolean\n=end\n    def has_next()\n\n    end\n\n\nend\n\n# Your BSTIterator object will be instantiated and called as such:\n# obj = BSTIterator.new(root)\n# param_1 = obj.next()\n# param_2 = obj.has_next()",
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                    "lang": "Scala",
                    "langSlug": "scala",
                    "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n *   var value: Int = _value\n *   var left: TreeNode = _left\n *   var right: TreeNode = _right\n * }\n */\nclass BSTIterator(_root: TreeNode) {\n\n    def next(): Int = {\n\n    }\n\n    def hasNext(): Boolean = {\n\n    }\n\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * var obj = new BSTIterator(root)\n * var param_1 = obj.next()\n * var param_2 = obj.hasNext()\n */",
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                    "lang": "Rust",
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                    "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n//   pub val: i32,\n//   pub left: Option<Rc<RefCell<TreeNode>>>,\n//   pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n//   #[inline]\n//   pub fn new(val: i32) -> Self {\n//     TreeNode {\n//       val,\n//       left: None,\n//       right: None\n//     }\n//   }\n// }\nstruct BSTIterator {\n\n}\n\n\n/**\n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl BSTIterator {\n\n    fn new(root: Option<Rc<RefCell<TreeNode>>>) -> Self {\n\n    }\n    \n    fn next(&self) -> i32 {\n\n    }\n    \n    fn has_next(&self) -> bool {\n\n    }\n}\n\n/**\n * Your BSTIterator object will be instantiated and called as such:\n * let obj = BSTIterator::new(root);\n * let ret_1: i32 = obj.next();\n * let ret_2: bool = obj.has_next();\n */",
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                    "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n  (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n  (tree-node val #f #f))\n\n|#\n\n(define bst-iterator%\n  (class object%\n    (super-new)\n\n    ; root : (or/c tree-node? #f)\n    (init-field\n      root)\n    \n    ; next : -> exact-integer?\n    (define/public (next)\n\n      )\n    ; has-next : -> boolean?\n    (define/public (has-next)\n\n      )))\n\n;; Your bst-iterator% object will be instantiated and called as such:\n;; (define obj (new bst-iterator% [root root]))\n;; (define param_1 (send obj next))\n;; (define param_2 (send obj has-next))",
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                    "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%%                     left = null  :: 'null' | #tree_node{},\n%%                     right = null :: 'null' | #tree_node{}}).\n\n-spec bst_iterator_init_(Root :: #tree_node{} | null) -> any().\nbst_iterator_init_(Root) ->\n  .\n\n-spec bst_iterator_next() -> integer().\nbst_iterator_next() ->\n  .\n\n-spec bst_iterator_has_next() -> boolean().\nbst_iterator_has_next() ->\n  .\n\n\n%% Your functions will be called as such:\n%% bst_iterator_init_(Root),\n%% Param_1 = bst_iterator_next(),\n%% Param_2 = bst_iterator_has_next(),\n\n%% bst_iterator_init_ will be called before every test case, in which you can do some necessary initializations.",
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                    "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           left: TreeNode.t() | nil,\n#           right: TreeNode.t() | nil\n#         }\n#   defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule BSTIterator do\n  @spec init_(root :: TreeNode.t | nil) :: any\n  def init_(root) do\n\n  end\n\n  @spec next() :: integer\n  def next() do\n\n  end\n\n  @spec has_next() :: boolean\n  def has_next() do\n\n  end\nend\n\n# Your functions will be called as such:\n# BSTIterator.init_(root)\n# param_1 = BSTIterator.next()\n# param_2 = BSTIterator.has_next()\n\n# BSTIterator.init_ will be called before every test case, in which you can do some necessary initializations.",
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