leetcode-problemset/leetcode-cn/originData/k-items-with-the-maximum-sum.json

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        "question": {
            "questionId": "2715",
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            "categoryTitle": "Algorithms",
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            "title": "K Items With the Maximum Sum",
            "titleSlug": "k-items-with-the-maximum-sum",
            "content": "<p>There is a bag that consists of items, each item&nbsp;has a number <code>1</code>, <code>0</code>, or <code>-1</code> written on it.</p>\n\n<p>You are given four <strong>non-negative </strong>integers <code>numOnes</code>, <code>numZeros</code>, <code>numNegOnes</code>, and <code>k</code>.</p>\n\n<p>The bag initially contains:</p>\n\n<ul>\n\t<li><code>numOnes</code> items with <code>1</code>s written on them.</li>\n\t<li><code>numZeroes</code> items with <code>0</code>s written on them.</li>\n\t<li><code>numNegOnes</code> items with <code>-1</code>s written on them.</li>\n</ul>\n\n<p>We want to pick exactly <code>k</code> items among the available items. Return <em>the <strong>maximum</strong> possible sum of numbers written on the items</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 2 items with 1 written on them and get a sum in a total of 2.\nIt can be proven that 2 is the maximum possible sum.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 3 items with 1 written on them, and 1 item with 0 written on it, and get a sum in a total of 3.\nIt can be proven that 3 is the maximum possible sum.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= numOnes, numZeros, numNegOnes &lt;= 50</code></li>\n\t<li><code>0 &lt;= k &lt;= numOnes + numZeros + numNegOnes</code></li>\n</ul>\n",
            "translatedTitle": "K 件物品的最大和",
            "translatedContent": "<p>袋子中装有一些物品，每个物品上都标记着数字 <code>1</code> 、<code>0</code> 或 <code>-1</code> 。</p>\n\n<p>给你四个非负整数 <code>numOnes</code> 、<code>numZeros</code> 、<code>numNegOnes</code> 和 <code>k</code> 。</p>\n\n<p>袋子最初包含：</p>\n\n<ul>\n\t<li><code>numOnes</code> 件标记为 <code>1</code> 的物品。</li>\n\t<li><code>numZeros</code> 件标记为 <code>0</code> 的物品。</li>\n\t<li><code>numNegOnes</code> 件标记为 <code>-1</code> 的物品。</li>\n</ul>\n\n<p>现计划从这些物品中恰好选出 <code>k</code> 件物品。返回所有可行方案中，物品上所标记数字之和的最大值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>袋子中的物品分别标记为 {1, 1, 1, 0, 0} 。取 2 件标记为 1 的物品，得到的数字之和为 2 。\n可以证明 2 是所有可行方案中的最大值。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4\n<strong>输出：</strong>3\n<strong>解释：</strong>袋子中的物品分别标记为 {1, 1, 1, 0, 0} 。取 3 件标记为 1 的物品，1 件标记为 0 的物品，得到的数字之和为 3 。\n可以证明 3 是所有可行方案中的最大值。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= numOnes, numZeros, numNegOnes &lt;= 50</code></li>\n\t<li><code>0 &lt;= k &lt;= numOnes + numZeros + numNegOnes</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int kItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def kItemsWithMaximumSum(self, numOnes, numZeros, numNegOnes, k):\n        \"\"\"\n        :type numOnes: int\n        :type numZeros: int\n        :type numNegOnes: int\n        :type k: int\n        :rtype: int\n        \"\"\"",
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                    "code": "public class Solution {\n    public int KItemsWithMaximumSum(int numOnes, int numZeros, int numNegOnes, int k) {\n\n    }\n}",
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                    "code": "# @param {Integer} num_ones\n# @param {Integer} num_zeros\n# @param {Integer} num_neg_ones\n# @param {Integer} k\n# @return {Integer}\ndef k_items_with_maximum_sum(num_ones, num_zeros, num_neg_ones, k)\n\nend",
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                    "code": "object Solution {\n    def kItemsWithMaximumSum(numOnes: Int, numZeros: Int, numNegOnes: Int, k: Int): Int = {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn k_items_with_maximum_sum(num_ones: i32, num_zeros: i32, num_neg_ones: i32, k: i32) -> i32 {\n\n    }\n}",
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                    "code": "-spec k_items_with_maximum_sum(NumOnes :: integer(), NumZeros :: integer(), NumNegOnes :: integer(), K :: integer()) -> integer().\nk_items_with_maximum_sum(NumOnes, NumZeros, NumNegOnes, K) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec k_items_with_maximum_sum(num_ones :: integer, num_zeros :: integer, num_neg_ones :: integer, k :: integer) :: integer\n  def k_items_with_maximum_sum(num_ones, num_zeros, num_neg_ones, k) do\n\n  end\nend",
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            "hints": [
                "It is always optimal to take items with the number 1 written on them as much as possible.",
                "If k > numOnes, after taking all items with the number 1, it is always optimal to take items with the number 0 written on them as much as possible.",
                "If k > numOnes + numZeroes we are forced to take k - numOnes - numZeroes -1s."
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