leetcode-problemset/leetcode-cn/originData/interleaving-string.json

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        "question": {
            "questionId": "97",
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            "categoryTitle": "Algorithms",
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            "title": "Interleaving String",
            "titleSlug": "interleaving-string",
            "content": "<p>Given strings <code>s1</code>, <code>s2</code>, and <code>s3</code>, find whether <code>s3</code> is formed by an <strong>interleaving</strong> of <code>s1</code> and <code>s2</code>.</p>\n\n<p>An <strong>interleaving</strong> of two strings <code>s</code> and <code>t</code> is a configuration where <code>s</code> and <code>t</code> are divided into <code>n</code> and <code>m</code> <span data-keyword=\"substring-nonempty\">substrings</span> respectively, such that:</p>\n\n<ul>\n\t<li><code>s = s<sub>1</sub> + s<sub>2</sub> + ... + s<sub>n</sub></code></li>\n\t<li><code>t = t<sub>1</sub> + t<sub>2</sub> + ... + t<sub>m</sub></code></li>\n\t<li><code>|n - m| &lt;= 1</code></li>\n\t<li>The <strong>interleaving</strong> is <code>s<sub>1</sub> + t<sub>1</sub> + s<sub>2</sub> + t<sub>2</sub> + s<sub>3</sub> + t<sub>3</sub> + ...</code> or <code>t<sub>1</sub> + s<sub>1</sub> + t<sub>2</sub> + s<sub>2</sub> + t<sub>3</sub> + s<sub>3</sub> + ...</code></li>\n</ul>\n\n<p><strong>Note:</strong> <code>a + b</code> is the concatenation of strings <code>a</code> and <code>b</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg\" style=\"width: 561px; height: 203px;\" />\n<pre>\n<strong>Input:</strong> s1 = &quot;aabcc&quot;, s2 = &quot;dbbca&quot;, s3 = &quot;aadbbcbcac&quot;\n<strong>Output:</strong> true\n<strong>Explanation:</strong> One way to obtain s3 is:\nSplit s1 into s1 = &quot;aa&quot; + &quot;bc&quot; + &quot;c&quot;, and s2 into s2 = &quot;dbbc&quot; + &quot;a&quot;.\nInterleaving the two splits, we get &quot;aa&quot; + &quot;dbbc&quot; + &quot;bc&quot; + &quot;a&quot; + &quot;c&quot; = &quot;aadbbcbcac&quot;.\nSince s3 can be obtained by interleaving s1 and s2, we return true.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;aabcc&quot;, s2 = &quot;dbbca&quot;, s3 = &quot;aadbbbaccc&quot;\n<strong>Output:</strong> false\n<strong>Explanation:</strong> Notice how it is impossible to interleave s2 with any other string to obtain s3.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;&quot;, s2 = &quot;&quot;, s3 = &quot;&quot;\n<strong>Output:</strong> true\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= s1.length, s2.length &lt;= 100</code></li>\n\t<li><code>0 &lt;= s3.length &lt;= 200</code></li>\n\t<li><code>s1</code>, <code>s2</code>, and <code>s3</code> consist of lowercase English letters.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong> Could you solve it using only <code>O(s2.length)</code> additional memory space?</p>\n",
            "translatedTitle": "交错字符串",
            "translatedContent": "<p>给定三个字符串&nbsp;<code>s1</code>、<code>s2</code>、<code>s3</code>，请你帮忙验证&nbsp;<code>s3</code>&nbsp;是否是由&nbsp;<code>s1</code>&nbsp;和&nbsp;<code>s2</code><em> </em><strong>交错 </strong>组成的。</p>\n\n<p>两个字符串 <code>s</code> 和 <code>t</code> <strong>交错</strong> 的定义与过程如下，其中每个字符串都会被分割成若干 <strong>非空</strong> 子字符串：</p>\n\n<ul>\n\t<li><code>s = s<sub>1</sub> + s<sub>2</sub> + ... + s<sub>n</sub></code></li>\n\t<li><code>t = t<sub>1</sub> + t<sub>2</sub> + ... + t<sub>m</sub></code></li>\n\t<li><code>|n - m| &lt;= 1</code></li>\n\t<li><strong>交错</strong> 是 <code>s<sub>1</sub> + t<sub>1</sub> + s<sub>2</sub> + t<sub>2</sub> + s<sub>3</sub> + t<sub>3</sub> + ...</code> 或者 <code>t<sub>1</sub> + s<sub>1</sub> + t<sub>2</sub> + s<sub>2</sub> + t<sub>3</sub> + s<sub>3</sub> + ...</code></li>\n</ul>\n\n<p><strong>注意：</strong><code>a + b</code> 意味着字符串 <code>a</code> 和 <code>b</code> 连接。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg\" />\n<pre>\n<strong>输入：</strong>s1 = \"aabcc\", s2 = \"dbbca\", s3 = \"aadbbcbcac\"\n<strong>输出：</strong>true\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"aabcc\", s2 = \"dbbca\", s3 = \"aadbbbaccc\"\n<strong>输出：</strong>false\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"\", s2 = \"\", s3 = \"\"\n<strong>输出：</strong>true\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= s1.length, s2.length &lt;= 100</code></li>\n\t<li><code>0 &lt;= s3.length &lt;= 200</code></li>\n\t<li><code>s1</code>、<code>s2</code>、和 <code>s3</code> 都由小写英文字母组成</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong>您能否仅使用 <code>O(s2.length)</code> 额外的内存空间来解决它?</p>\n",
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