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leetcode-problemset/leetcode-cn/originData/h-index-ii.json
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{
"data": {
"question": {
"questionId": "275",
"questionFrontendId": "275",
"categoryTitle": "Algorithms",
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"title": "H-Index II",
"titleSlug": "h-index-ii",
"content": "<p>Given an array of integers <code>citations</code> where <code>citations[i]</code> is the number of citations a researcher received for their <code>i<sup>th</sup></code> paper and <code>citations</code> is sorted in <strong>ascending order</strong>, return <em>the researcher&#39;s h-index</em>.</p>\n\n<p>According to the <a href=\"https://en.wikipedia.org/wiki/H-index\" target=\"_blank\">definition of h-index on Wikipedia</a>: The h-index is defined as the maximum value of <code>h</code> such that the given researcher has published at least <code>h</code> papers that have each been cited at least <code>h</code> times.</p>\n\n<p>You must write an algorithm that runs in logarithmic time.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> citations = [0,1,3,5,6]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> [0,1,3,5,6] means the researcher has 5 papers in total and each of them had received 0, 1, 3, 5, 6 citations respectively.\nSince the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, their h-index is 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> citations = [1,2,100]\n<strong>Output:</strong> 2\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == citations.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= citations[i] &lt;= 1000</code></li>\n\t<li><code>citations</code> is sorted in <strong>ascending order</strong>.</li>\n</ul>\n",
"translatedTitle": "H 指数 II",
"translatedContent": "<p>给你一个整数数组 <code>citations</code> ,其中 <code>citations[i]</code> 表示研究者的第 <code>i</code> 篇论文被引用的次数,<code>citations</code> 已经按照&nbsp;<strong>升序排列&nbsp;</strong>。计算并返回该研究者的 h<strong><em>&nbsp;</em></strong>指数。</p>\n\n<p><a href=\"https://baike.baidu.com/item/h-index/3991452?fr=aladdin\" target=\"_blank\">h 指数的定义</a>h 代表“高引用次数”high citations一名科研人员的 <code>h</code> 指数是指他(她)的 <code>n</code> 篇论文中)<strong>至少&nbsp;</strong>有 <code>h</code> 篇论文分别被引用了<strong>至少</strong> <code>h</code> 次。</p>\n\n<p>请你设计并实现对数时间复杂度的算法解决此问题。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong><code>citations = [0,1,3,5,6]</code>\n<strong>输出:</strong><code>3</code>\n<strong>解释:</strong>给定数组表示研究者总共有 <code>5</code> 篇论文,每篇论文相应的被引用了 <code>0, 1, 3, 5, 6</code> 次。\n&nbsp; 由于研究者有<code>3</code>篇论文每篇<strong> 至少 </strong>被引用了 <code>3</code> 次,其余两篇论文每篇被引用<strong> 不多于</strong> <code>3</code> 次,所以她的<em> h </em>指数是 <code>3</code> 。</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong><code>citations = [1,2,100]</code>\n<strong>输出:</strong><code>2</code>\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>n == citations.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= citations[i] &lt;= 1000</code></li>\n\t<li><code>citations</code> 按 <strong>升序排列</strong></li>\n</ul>\n",
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"name": "Array",
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"translatedName": "数组",
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"code": "class Solution {\npublic:\n int hIndex(vector<int>& citations) {\n\n }\n};",
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"code": "class Solution(object):\n def hIndex(self, citations):\n \"\"\"\n :type citations: List[int]\n :rtype: int\n \"\"\"",
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"code": "class Solution {\n fun hIndex(citations: IntArray): Int {\n\n }\n}",
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"code": "class Solution {\n int hIndex(List<int> citations) {\n \n }\n}",
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"code": "impl Solution {\n pub fn h_index(citations: Vec<i32>) -> i32 {\n\n }\n}",
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"code": "defmodule Solution do\n @spec h_index(citations :: [integer]) :: integer\n def h_index(citations) do\n \n end\nend",
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"Expected runtime complexity is in <i>O</i>(log <i>n</i>) and the input is sorted."
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