leetcode-problemset/leetcode-cn/originData/find-the-maximum-achievable-number.json

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            "title": "Find the Maximum Achievable Number",
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            "content": "<p>You are given two integers, <code>num</code> and <code>t</code>.</p>\n\n<p>An integer <code>x</code> is called <b>achievable</b> if it can become equal to <code>num</code> after applying the following operation no more than <code>t</code> times:</p>\n\n<ul>\n\t<li>Increase or decrease <code>x</code> by <code>1</code>, and simultaneously increase or decrease <code>num</code> by <code>1</code>.</li>\n</ul>\n\n<p>Return <em>the maximum possible achievable number</em>. It can be proven that there exists at least one achievable number.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 4, t = 1\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The maximum achievable number is x = 6; it can become equal to num after performing this operation:\n1- Decrease x by 1, and increase num by 1. Now, x = 5 and num = 5. \nIt can be proven that there is no achievable number larger than 6.\n\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 3, t = 2\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> The maximum achievable number is x = 7; after performing these operations, x will equal num: \n1- Decrease x by 1, and increase num by 1. Now, x = 6 and num = 4.\n2- Decrease x by 1, and increase num by 1. Now, x = 5 and num = 5.\nIt can be proven that there is no achievable number larger than 7.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num, t&nbsp;&lt;= 50</code></li>\n</ul>\n",
            "translatedTitle": "找出最大的可达成数字",
            "translatedContent": "<p>给你两个整数 <code>num</code> 和 <code>t</code> 。</p>\n\n<p>如果整数 <code>x</code> 可以在执行下述操作不超过 <code>t</code> 次的情况下变为与 <code>num</code> 相等，则称其为 <strong>可达成数字</strong> ：</p>\n\n<ul>\n\t<li>每次操作将 <code>x</code> 的值增加或减少 <code>1</code> ，同时可以选择将 <code>num</code> 的值增加或减少 <code>1</code> 。</li>\n</ul>\n\n<p>返回所有可达成数字中的最大值。可以证明至少存在一个可达成数字。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>num = 4, t = 1\n<strong>输出：</strong>6\n<strong>解释：</strong>最大可达成数字是 x = 6 ，执行下述操作可以使其等于 num ：\n- x 减少 1 ，同时 num 增加 1 。此时，x = 5 且 num = 5 。 \n可以证明不存在大于 6 的可达成数字。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>num = 3, t = 2\n<strong>输出：</strong>7\n<strong>解释：</strong>最大的可达成数字是 x = 7 ，执行下述操作可以使其等于 num ：\n- x 减少 1 ，同时 num 增加 1 。此时，x = 6 且 num = 4 。 \n- x 减少 1 ，同时 num 增加 1 。此时，x = 5 且 num = 5 。 \n可以证明不存在大于 7 的可达成数字。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num, t&nbsp;&lt;= 50</code></li>\n</ul>\n",
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