leetcode-problemset/leetcode-cn/originData/find-the-k-beauty-of-a-number.json

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            "questionId": "1430",
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            "categoryTitle": "Algorithms",
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            "title": "Find the K-Beauty of a Number",
            "titleSlug": "find-the-k-beauty-of-a-number",
            "content": "<p>The <strong>k-beauty</strong> of an integer <code>num</code> is defined as the number of <strong>substrings</strong> of <code>num</code> when it is read as a string that meet the following conditions:</p>\n\n<ul>\n\t<li>It has a length of <code>k</code>.</li>\n\t<li>It is a divisor of <code>num</code>.</li>\n</ul>\n\n<p>Given integers <code>num</code> and <code>k</code>, return <em>the k-beauty of </em><code>num</code>.</p>\n\n<p>Note:</p>\n\n<ul>\n\t<li><strong>Leading zeros</strong> are allowed.</li>\n\t<li><code>0</code> is not a divisor of any value.</li>\n</ul>\n\n<p>A <strong>substring</strong> is a contiguous sequence of characters in a string.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 240, k = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The following are the substrings of num of length k:\n- &quot;24&quot; from &quot;<strong><u>24</u></strong>0&quot;: 24 is a divisor of 240.\n- &quot;40&quot; from &quot;2<u><strong>40</strong></u>&quot;: 40 is a divisor of 240.\nTherefore, the k-beauty is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> num = 430043, k = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The following are the substrings of num of length k:\n- &quot;43&quot; from &quot;<u><strong>43</strong></u>0043&quot;: 43 is a divisor of 430043.\n- &quot;30&quot; from &quot;4<u><strong>30</strong></u>043&quot;: 30 is not a divisor of 430043.\n- &quot;00&quot; from &quot;43<u><strong>00</strong></u>43&quot;: 0 is not a divisor of 430043.\n- &quot;04&quot; from &quot;430<u><strong>04</strong></u>3&quot;: 4 is not a divisor of 430043.\n- &quot;43&quot; from &quot;4300<u><strong>43</strong></u>&quot;: 43 is a divisor of 430043.\nTherefore, the k-beauty is 2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= num.length</code> (taking <code>num</code> as a string)</li>\n</ul>\n",
            "translatedTitle": "找到一个数字的 K 美丽值",
            "translatedContent": "<p>一个整数 <code>num</code>&nbsp;的&nbsp;<strong>k&nbsp;</strong>美丽值定义为&nbsp;<code>num</code>&nbsp;中符合以下条件的&nbsp;<strong>子字符串</strong>&nbsp;数目：</p>\n\n<ul>\n\t<li>子字符串长度为&nbsp;<code>k</code>&nbsp;。</li>\n\t<li>子字符串能整除 <code>num</code> 。</li>\n</ul>\n\n<p>给你整数&nbsp;<code>num</code> 和&nbsp;<code>k</code>&nbsp;，请你返回<em>&nbsp;</em><code>num</code>&nbsp;的 k 美丽值。</p>\n\n<p>注意：</p>\n\n<ul>\n\t<li>允许有&nbsp;<strong>前缀</strong>&nbsp;<strong>0</strong>&nbsp;。</li>\n\t<li><code>0</code>&nbsp;不能整除任何值。</li>\n</ul>\n\n<p>一个 <strong>子字符串</strong>&nbsp;是一个字符串里的连续一段字符序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>num = 240, k = 2\n<b>输出：</b>2\n<b>解释：</b>以下是 num 里长度为 k 的子字符串：\n- \"<em><strong>24</strong></em>0\" 中的 \"24\" ：24 能整除 240 。\n- \"2<em><strong>40</strong></em>\" 中的 \"40\" ：40 能整除 240 。\n所以，k 美丽值为 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>num = 430043, k = 2\n<b>输出：</b>2\n<b>解释：</b>以下是 num 里长度为 k 的子字符串：\n- \"<em><strong>43</strong></em>0043\" 中的 \"43\" ：43 能整除 430043 。\n- \"4<em><strong>30</strong></em>043\" 中的 \"30\" ：30 不能整除 430043 。\n- \"43<em><strong>00</strong></em>43\" 中的 \"00\" ：0 不能整除 430043 。\n- \"430<em><strong>04</strong></em>3\" 中的 \"04\" ：4 不能整除 430043 。\n- \"4300<em><strong>43</strong></em>\" 中的 \"43\" ：43 能整除 430043 。\n所以，k 美丽值为 2 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= num &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= num.length</code>&nbsp;（将&nbsp;<code>num</code>&nbsp;视为字符串）</li>\n</ul>\n",
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                "We should check all the substrings of num with a length of k and see if it is a divisor of num.",
                "We can more easily obtain the substrings by converting num into a string and converting back to an integer to check for divisibility."
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