leetcode-problemset/leetcode-cn/originData/determine-if-a-cell-is-reachable-at-a-given-time.json

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            "title": "Determine if a Cell Is Reachable at a Given Time",
            "titleSlug": "determine-if-a-cell-is-reachable-at-a-given-time",
            "content": "<p>You are given four integers <code>sx</code>, <code>sy</code>, <code>fx</code>, <code>fy</code>, and a <strong>non-negative</strong> integer <code>t</code>.</p>\n\n<p>In an infinite 2D grid, you start at the cell <code>(sx, sy)</code>. Each second, you <strong>must</strong> move to any of its adjacent cells.</p>\n\n<p>Return <code>true</code> <em>if you can reach cell </em><code>(fx, fy)</code> <em>after<strong> exactly</strong></em> <code>t</code> <strong><em>seconds</em></strong>, <em>or</em> <code>false</code> <em>otherwise</em>.</p>\n\n<p>A cell&#39;s <strong>adjacent cells</strong> are the 8 cells around it that share at least one corner with it. You can visit the same cell several times.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/08/05/example2.svg\" style=\"width: 443px; height: 243px;\" />\n<pre>\n<strong>Input:</strong> sx = 2, sy = 4, fx = 7, fy = 7, t = 6\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Starting at cell (2, 4), we can reach cell (7, 7) in exactly 6 seconds by going through the cells depicted in the picture above. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/08/05/example1.svg\" style=\"width: 383px; height: 202px;\" />\n<pre>\n<strong>Input:</strong> sx = 3, sy = 1, fx = 7, fy = 3, t = 3\n<strong>Output:</strong> false\n<strong>Explanation:</strong> Starting at cell (3, 1), it takes at least 4 seconds to reach cell (7, 3) by going through the cells depicted in the picture above. Hence, we cannot reach cell (7, 3) at the third second.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= sx, sy, fx, fy &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= t &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "判断能否在给定时间到达单元格",
            "translatedContent": "<p>给你四个整数 <code>sx</code>、<code>sy</code>、<code>fx</code>、<code>fy</code>&nbsp; 以及一个 <strong>非负整数</strong> <code>t</code> 。</p>\n\n<p>在一个无限的二维网格中，你从单元格 <code>(sx, sy)</code> 开始出发。每一秒，你 <strong>必须</strong> 移动到任一与之前所处单元格相邻的单元格中。</p>\n\n<p>如果你能在 <strong>恰好 </strong><code>t</code><strong> 秒</strong> 后到达单元格<em> </em><code>(fx, fy)</code> ，返回 <code>true</code> ；否则，返回&nbsp; <code>false</code> 。</p>\n\n<p>单元格的 <strong>相邻单元格</strong> 是指该单元格周围与其至少共享一个角的 8 个单元格。你可以多次访问同一个单元格。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/08/05/example2.svg\" style=\"width: 443px; height: 243px;\" />\n<pre>\n<strong>输入：</strong>sx = 2, sy = 4, fx = 7, fy = 7, t = 6\n<strong>输出：</strong>true\n<strong>解释：</strong>从单元格 (2, 4) 开始出发，穿过上图标注的单元格，可以在恰好 6 秒后到达单元格 (7, 7) 。 \n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/08/05/example1.svg\" style=\"width: 383px; height: 202px;\" />\n<pre>\n<strong>输入：</strong>sx = 3, sy = 1, fx = 7, fy = 3, t = 3\n<strong>输出：</strong>false\n<strong>解释：</strong>从单元格 (3, 1) 开始出发，穿过上图标注的单元格，至少需要 4 秒后到达单元格 (7, 3) 。 因此，无法在 3 秒后到达单元格 (7, 3) 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= sx, sy, fx, fy &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= t &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                "Minimum time to reach the cell should be less than or equal to given time.",
                "The answer is true if <code>t</code> is greater or equal than the Chebyshev distance from <code>(sx, sy)</code> to <code>(fx, fy)</code>. However, there is one more edge case to be considered.",
                "The answer is false If <code>sx == fx</code> and <code>sy == fy</code>"
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