mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
25 KiB
JSON
174 lines
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"content": "<p>A message containing letters from <code>A-Z</code> can be <strong>encoded</strong> into numbers using the following mapping:</p>\n\n<pre>\n'A' -> "1"\n'B' -> "2"\n...\n'Z' -> "26"\n</pre>\n\n<p>To <strong>decode</strong> an encoded message, all the digits must be grouped then mapped back into letters using the reverse of the mapping above (there may be multiple ways). For example, <code>"11106"</code> can be mapped into:</p>\n\n<ul>\n\t<li><code>"AAJF"</code> with the grouping <code>(1 1 10 6)</code></li>\n\t<li><code>"KJF"</code> with the grouping <code>(11 10 6)</code></li>\n</ul>\n\n<p>Note that the grouping <code>(1 11 06)</code> is invalid because <code>"06"</code> cannot be mapped into <code>'F'</code> since <code>"6"</code> is different from <code>"06"</code>.</p>\n\n<p><strong>In addition</strong> to the mapping above, an encoded message may contain the <code>'*'</code> character, which can represent any digit from <code>'1'</code> to <code>'9'</code> (<code>'0'</code> is excluded). For example, the encoded message <code>"1*"</code> may represent any of the encoded messages <code>"11"</code>, <code>"12"</code>, <code>"13"</code>, <code>"14"</code>, <code>"15"</code>, <code>"16"</code>, <code>"17"</code>, <code>"18"</code>, or <code>"19"</code>. Decoding <code>"1*"</code> is equivalent to decoding <strong>any</strong> of the encoded messages it can represent.</p>\n\n<p>Given a string <code>s</code> consisting of digits and <code>'*'</code> characters, return <em>the <strong>number</strong> of ways to <strong>decode</strong> it</em>.</p>\n\n<p>Since the answer may be very large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "*"\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> The encoded message can represent any of the encoded messages "1", "2", "3", "4", "5", "6", "7", "8", or "9".\nEach of these can be decoded to the strings "A", "B", "C", "D", "E", "F", "G", "H", and "I" respectively.\nHence, there are a total of 9 ways to decode "*".\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "1*"\n<strong>Output:</strong> 18\n<strong>Explanation:</strong> The encoded message can represent any of the encoded messages "11", "12", "13", "14", "15", "16", "17", "18", or "19".\nEach of these encoded messages have 2 ways to be decoded (e.g. "11" can be decoded to "AA" or "K").\nHence, there are a total of 9 * 2 = 18 ways to decode "1*".\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = "2*"\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> The encoded message can represent any of the encoded messages "21", "22", "23", "24", "25", "26", "27", "28", or "29".\n"21", "22", "23", "24", "25", and "26" have 2 ways of being decoded, but "27", "28", and "29" only have 1 way.\nHence, there are a total of (6 * 2) + (3 * 1) = 12 + 3 = 15 ways to decode "2*".\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> is a digit or <code>'*'</code>.</li>\n</ul>\n",
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"translatedTitle": "解码方法 II",
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"translatedContent": "<p>一条包含字母 <code>A-Z</code> 的消息通过以下的方式进行了 <strong>编码</strong> ：</p>\n\n<pre>\n'A' -> \"1\"\n'B' -> \"2\"\n...\n'Z' -> \"26\"</pre>\n\n<p>要 <strong>解码</strong> 一条已编码的消息，所有的数字都必须分组，然后按原来的编码方案反向映射回字母（可能存在多种方式）。例如，<code>\"11106\"</code> 可以映射为：</p>\n\n<ul>\n\t<li><code>\"AAJF\"</code> 对应分组 <code>(1 1 10 6)</code></li>\n\t<li><code>\"KJF\"</code> 对应分组 <code>(11 10 6)</code></li>\n</ul>\n\n<p>注意，像 <code>(1 11 06)</code> 这样的分组是无效的，因为 <code>\"06\"</code> 不可以映射为 <code>'F'</code> ，因为 <code>\"6\"</code> 与 <code>\"06\"</code> 不同。</p>\n\n<p><strong>除了</strong> 上面描述的数字字母映射方案，编码消息中可能包含 <code>'*'</code> 字符，可以表示从 <code>'1'</code> 到 <code>'9'</code> 的任一数字（不包括 <code>'0'</code>）。例如，编码字符串 <code>\"1*\"</code> 可以表示 <code>\"11\"</code>、<code>\"12\"</code>、<code>\"13\"</code>、<code>\"14\"</code>、<code>\"15\"</code>、<code>\"16\"</code>、<code>\"17\"</code>、<code>\"18\"</code> 或 <code>\"19\"</code> 中的任意一条消息。对 <code>\"1*\"</code> 进行解码，相当于解码该字符串可以表示的任何编码消息。</p>\n\n<p>给你一个字符串 <code>s</code> ，由数字和 <code>'*'</code> 字符组成，返回 <strong>解码</strong> 该字符串的方法 <strong>数目</strong> 。</p>\n\n<p>由于答案数目可能非常大，返回 <code>10<sup>9</sup> + 7</code> 的 <b>模</b> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"*\"\n<strong>输出：</strong>9\n<strong>解释：</strong>这一条编码消息可以表示 \"1\"、\"2\"、\"3\"、\"4\"、\"5\"、\"6\"、\"7\"、\"8\" 或 \"9\" 中的任意一条。\n可以分别解码成字符串 \"A\"、\"B\"、\"C\"、\"D\"、\"E\"、\"F\"、\"G\"、\"H\" 和 \"I\" 。\n因此，\"*\" 总共有 9 种解码方法。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"1*\"\n<strong>输出：</strong>18\n<strong>解释：</strong>这一条编码消息可以表示 \"11\"、\"12\"、\"13\"、\"14\"、\"15\"、\"16\"、\"17\"、\"18\" 或 \"19\" 中的任意一条。\n每种消息都可以由 2 种方法解码（例如，\"11\" 可以解码成 \"AA\" 或 \"K\"）。\n因此，\"1*\" 共有 9 * 2 = 18 种解码方法。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"2*\"\n<strong>输出：</strong>15\n<strong>解释：</strong>这一条编码消息可以表示 \"21\"、\"22\"、\"23\"、\"24\"、\"25\"、\"26\"、\"27\"、\"28\" 或 \"29\" 中的任意一条。\n\"21\"、\"22\"、\"23\"、\"24\"、\"25\" 和 \"26\" 由 2 种解码方法，但 \"27\"、\"28\" 和 \"29\" 仅有 1 种解码方法。\n因此，\"2*\" 共有 (6 * 2) + (3 * 1) = 12 + 3 = 15 种解码方法。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 10<sup>5</sup></code></li>\n\t<li><code>s[i]</code> 是 <code>0 - 9</code> 中的一位数字或字符 <code>'*'</code></li>\n</ul>\n",
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