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leetcode-problemset/leetcode-cn/originData/count-subarrays-where-max-element-appears-at-least-k-times.json
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"categoryTitle": "Algorithms",
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"title": "Count Subarrays Where Max Element Appears at Least K Times",
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"content": "<p>You are given an integer array <code>nums</code> and a <strong>positive</strong> integer <code>k</code>.</p>\n\n<p>Return <em>the number of subarrays where the <strong>maximum</strong> element of </em><code>nums</code><em> appears <strong>at least</strong> </em><code>k</code><em> times in that subarray.</em></p>\n\n<p>A <strong>subarray</strong> is a contiguous sequence of elements within an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,2,3,3], k = 2\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The subarrays that contain the element 3 at least 2 times are: [1,3,2,3], [1,3,2,3,3], [3,2,3], [3,2,3,3], [2,3,3] and [3,3].\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,4,2,1], k = 3\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> No subarray contains the element 4 at least 3 times.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
"translatedTitle": "统计最大元素出现至少 K 次的子数组",
"translatedContent": "<p>给你一个整数数组 <code>nums</code> 和一个 <strong>正整数</strong> <code>k</code> 。</p>\n\n<p>请你统计有多少满足 「&nbsp;<code>nums</code> 中的 <strong>最大</strong> 元素」至少出现 <code>k</code> 次的子数组,并返回满足这一条件的子数组的数目。</p>\n\n<p>子数组是数组中的一个连续元素序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,3,2,3,3], k = 2\n<strong>输出:</strong>6\n<strong>解释:</strong>包含元素 3 至少 2 次的子数组为:[1,3,2,3]、[1,3,2,3,3]、[3,2,3]、[3,2,3,3]、[2,3,3] 和 [3,3] 。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [1,4,2,1], k = 3\n<strong>输出:</strong>0\n<strong>解释:</strong>没有子数组包含元素 4 至少 3 次。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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