leetcode-problemset/leetcode-cn/originData/count-equal-and-divisible-pairs-in-an-array.json

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        "question": {
            "questionId": "2277",
            "questionFrontendId": "2176",
            "categoryTitle": "Algorithms",
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            "title": "Count Equal and Divisible Pairs in an Array",
            "titleSlug": "count-equal-and-divisible-pairs-in-an-array",
            "content": "Given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code> and an integer <code>k</code>, return <em>the <strong>number of pairs</strong></em> <code>(i, j)</code> <em>where</em> <code>0 &lt;= i &lt; j &lt; n</code>, <em>such that</em> <code>nums[i] == nums[j]</code> <em>and</em> <code>(i * j)</code> <em>is divisible by</em> <code>k</code>.\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,1,2,2,2,1,3], k = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong>\nThere are 4 pairs that meet all the requirements:\n- nums[0] == nums[6], and 0 * 6 == 0, which is divisible by 2.\n- nums[2] == nums[3], and 2 * 3 == 6, which is divisible by 2.\n- nums[2] == nums[4], and 2 * 4 == 8, which is divisible by 2.\n- nums[3] == nums[4], and 3 * 4 == 12, which is divisible by 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4], k = 1\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> Since no value in nums is repeated, there are no pairs (i,j) that meet all the requirements.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i], k &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "统计数组中相等且可以被整除的数对",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始长度为 <code>n</code>&nbsp;的整数数组&nbsp;<code>nums</code>&nbsp;和一个整数&nbsp;<code>k</code>&nbsp;，请你返回满足&nbsp;<code>0 &lt;= i &lt; j &lt; n</code>&nbsp;，<code>nums[i] == nums[j]</code> 且&nbsp;<code>(i * j)</code>&nbsp;能被&nbsp;<code>k</code>&nbsp;整除的数对&nbsp;<code>(i, j)</code>&nbsp;的&nbsp;<strong>数目</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [3,1,2,2,2,1,3], k = 2\n<b>输出：</b>4\n<strong>解释：</strong>\n总共有 4 对数符合所有要求：\n- nums[0] == nums[6] 且 0 * 6 == 0 ，能被 2 整除。\n- nums[2] == nums[3] 且 2 * 3 == 6 ，能被 2 整除。\n- nums[2] == nums[4] 且 2 * 4 == 8 ，能被 2 整除。\n- nums[3] == nums[4] 且 3 * 4 == 12 ，能被 2 整除。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [1,2,3,4], k = 1\n<b>输出：</b>0\n<b>解释：</b>由于数组中没有重复数值，所以没有数对 (i,j) 符合所有要求。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i], k &lt;= 100</code></li>\n</ul>\n",
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