leetcode-problemset/leetcode-cn/originData/contains-duplicate-ii.json

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            "title": "Contains Duplicate II",
            "titleSlug": "contains-duplicate-ii",
            "content": "<p>Given an integer array <code>nums</code> and an integer <code>k</code>, return <code>true</code> <em>if there are two <strong>distinct indices</strong> </em><code>i</code><em> and </em><code>j</code><em> in the array such that </em><code>nums[i] == nums[j]</code><em> and </em><code>abs(i - j) &lt;= k</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,1], k = 3\n<strong>Output:</strong> true\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,0,1,1], k = 1\n<strong>Output:</strong> true\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,1,2,3], k = 2\n<strong>Output:</strong> false\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "存在重复元素 II",
            "translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code> 和一个整数&nbsp;<code>k</code> ，判断数组中是否存在两个 <strong>不同的索引</strong><em>&nbsp;</em><code>i</code>&nbsp;和<em>&nbsp;</em><code>j</code> ，满足 <code>nums[i] == nums[j]</code> 且 <code>abs(i - j) &lt;= k</code> 。如果存在，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,1], k<em> </em>= 3\n<strong>输出：</strong>true</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,0,1,1], k<em> </em>=<em> </em>1\n<strong>输出：</strong>true</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,1,2,3], k<em> </em>=<em> </em>2\n<strong>输出：</strong>false</pre>\n\n<p>&nbsp;</p>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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