mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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192 lines
28 KiB
JSON
192 lines
28 KiB
JSON
{
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"question": {
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"questionId": "105",
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"questionFrontendId": "105",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1168,
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"title": "Construct Binary Tree from Preorder and Inorder Traversal",
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"content": "<p>Given two integer arrays <code>preorder</code> and <code>inorder</code> where <code>preorder</code> is the preorder traversal of a binary tree and <code>inorder</code> is the inorder traversal of the same tree, construct and return <em>the binary tree</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/tree.jpg\" style=\"width: 277px; height: 302px;\" />\n<pre>\n<strong>Input:</strong> preorder = [3,9,20,15,7], inorder = [9,3,15,20,7]\n<strong>Output:</strong> [3,9,20,null,null,15,7]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> preorder = [-1], inorder = [-1]\n<strong>Output:</strong> [-1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= preorder.length <= 3000</code></li>\n\t<li><code>inorder.length == preorder.length</code></li>\n\t<li><code>-3000 <= preorder[i], inorder[i] <= 3000</code></li>\n\t<li><code>preorder</code> and <code>inorder</code> consist of <strong>unique</strong> values.</li>\n\t<li>Each value of <code>inorder</code> also appears in <code>preorder</code>.</li>\n\t<li><code>preorder</code> is <strong>guaranteed</strong> to be the preorder traversal of the tree.</li>\n\t<li><code>inorder</code> is <strong>guaranteed</strong> to be the inorder traversal of the tree.</li>\n</ul>\n",
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"translatedTitle": "从前序与中序遍历序列构造二叉树",
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"translatedContent": "<p>给定两个整数数组 <code>preorder</code> 和 <code>inorder</code> ，其中 <code>preorder</code> 是二叉树的<strong>先序遍历</strong>， <code>inorder</code> 是同一棵树的<strong>中序遍历</strong>，请构造二叉树并返回其根节点。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/tree.jpg\" style=\"height: 302px; width: 277px;\" />\n<pre>\n<strong>输入</strong><strong>:</strong> preorder = [3,9,20,15,7], inorder = [9,3,15,20,7]\n<strong>输出:</strong> [3,9,20,null,null,15,7]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong> preorder = [-1], inorder = [-1]\n<strong>输出:</strong> [-1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= preorder.length <= 3000</code></li>\n\t<li><code>inorder.length == preorder.length</code></li>\n\t<li><code>-3000 <= preorder[i], inorder[i] <= 3000</code></li>\n\t<li><code>preorder</code> 和 <code>inorder</code> 均 <strong>无重复</strong> 元素</li>\n\t<li><code>inorder</code> 均出现在 <code>preorder</code></li>\n\t<li><code>preorder</code> <strong>保证</strong> 为二叉树的前序遍历序列</li>\n\t<li><code>inorder</code> <strong>保证</strong> 为二叉树的中序遍历序列</li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) {\n\n }\n};",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def buildTree(self, preorder, inorder):\n \"\"\"\n :type preorder: List[int]\n :type inorder: List[int]\n :rtype: TreeNode\n \"\"\"\n ",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode BuildTree(int[] preorder, int[] inorder) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {number[]} preorder\n * @param {number[]} inorder\n * @return {TreeNode}\n */\nvar buildTree = function(preorder, inorder) {\n\n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction buildTree(preorder: number[], inorder: number[]): TreeNode | null {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param Integer[] $preorder\n * @param Integer[] $inorder\n * @return TreeNode\n */\n function buildTree($preorder, $inorder) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func buildTree(_ preorder: [Int], _ inorder: [Int]) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun buildTree(preorder: IntArray, inorder: IntArray): TreeNode? {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? buildTree(List<int> preorder, List<int> inorder) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc buildTree(preorder []int, inorder []int) *TreeNode {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {Integer[]} preorder\n# @param {Integer[]} inorder\n# @return {TreeNode}\ndef build_tree(preorder, inorder)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def buildTree(preorder: Array[Int], inorder: Array[Int]): TreeNode = {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec build_tree(preorder :: [integer], inorder :: [integer]) :: TreeNode.t | nil\n def build_tree(preorder, inorder) do\n \n end\nend",
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