leetcode-problemset/leetcode-cn/originData/battleships-in-a-board.json

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            "title": "Battleships in a Board",
            "titleSlug": "battleships-in-a-board",
            "content": "<p>Given an <code>m x n</code> matrix <code>board</code> where each cell is a battleship <code>&#39;X&#39;</code> or empty <code>&#39;.&#39;</code>, return <em>the number of the <strong>battleships</strong> on</em> <code>board</code>.</p>\n\n<p><strong>Battleships</strong> can only be placed horizontally or vertically on <code>board</code>. In other words, they can only be made of the shape <code>1 x k</code> (<code>1</code> row, <code>k</code> columns) or <code>k x 1</code> (<code>k</code> rows, <code>1</code> column), where <code>k</code> can be of any size. At least one horizontal or vertical cell separates between two battleships (i.e., there are no adjacent battleships).</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/10/battelship-grid.jpg\" style=\"width: 333px; height: 333px;\" />\n<pre>\n<strong>Input:</strong> board = [[&quot;X&quot;,&quot;.&quot;,&quot;.&quot;,&quot;X&quot;],[&quot;.&quot;,&quot;.&quot;,&quot;.&quot;,&quot;X&quot;],[&quot;.&quot;,&quot;.&quot;,&quot;.&quot;,&quot;X&quot;]]\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> board = [[&quot;.&quot;]]\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 200</code></li>\n\t<li><code>board[i][j]</code> is either <code>&#39;.&#39;</code> or <code>&#39;X&#39;</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong> Could you do it in one-pass, using only <code>O(1)</code> extra memory and without modifying the values <code>board</code>?</p>\n",
            "translatedTitle": "甲板上的战舰",
            "translatedContent": "<p>给你一个大小为 <code>m x n</code> 的矩阵 <code>board</code> 表示甲板，其中，每个单元格可以是一艘战舰 <code>'X'</code> 或者是一个空位 <code>'.'</code> ，返回在甲板 <code>board</code> 上放置的 <strong>战舰</strong> 的数量。</p>\n\n<p><strong>战舰</strong> 只能水平或者垂直放置在 <code>board</code> 上。换句话说，战舰只能按 <code>1 x k</code>（<code>1</code> 行，<code>k</code> 列）或 <code>k x 1</code>（<code>k</code> 行，<code>1</code> 列）的形状建造，其中 <code>k</code> 可以是任意大小。两艘战舰之间至少有一个水平或垂直的空位分隔 （即没有相邻的战舰）。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/10/battelship-grid.jpg\" style=\"width: 333px; height: 333px;\" />\n<pre>\n<strong>输入：</strong>board = [[\"X\",\".\",\".\",\"X\"],[\".\",\".\",\".\",\"X\"],[\".\",\".\",\".\",\"X\"]]\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>board = [[\".\"]]\n<strong>输出：</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 200</code></li>\n\t<li><code>board[i][j]</code> 是 <code>'.'</code> 或 <code>'X'</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong>你可以实现一次扫描算法，并只使用<strong> </strong><code>O(1)</code><strong> </strong>额外空间，并且不修改 <code>board</code> 的值来解决这个问题吗？</p>\n",
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