mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
185 lines
20 KiB
JSON
185 lines
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"title": "Array Partition I",
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"content": "<p>Given an integer array <code>nums</code> of <code>2n</code> integers, group these integers into <code>n</code> pairs <code>(a<sub>1</sub>, b<sub>1</sub>), (a<sub>2</sub>, b<sub>2</sub>), ..., (a<sub>n</sub>, b<sub>n</sub>)</code> such that the sum of <code>min(a<sub>i</sub>, b<sub>i</sub>)</code> for all <code>i</code> is <strong>maximized</strong>. Return<em> the maximized sum</em>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,4,3,2]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> All possible pairings (ignoring the ordering of elements) are:\n1. (1, 4), (2, 3) -> min(1, 4) + min(2, 3) = 1 + 2 = 3\n2. (1, 3), (2, 4) -> min(1, 3) + min(2, 4) = 1 + 2 = 3\n3. (1, 2), (3, 4) -> min(1, 2) + min(3, 4) = 1 + 3 = 4\nSo the maximum possible sum is 4.</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [6,2,6,5,1,2]\n<strong>Output:</strong> 9\n<strong>Explanation:</strong> The optimal pairing is (2, 1), (2, 5), (6, 6). min(2, 1) + min(2, 5) + min(6, 6) = 1 + 2 + 6 = 9.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= n <= 10<sup>4</sup></code></li>\n\t<li><code>nums.length == 2 * n</code></li>\n\t<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>\n</ul>\n",
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"translatedTitle": "数组拆分 I",
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"Obviously, brute force won't help here. Think of something else, take some example like 1,2,3,4.",
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"How will you make pairs to get the result? There must be some pattern.",
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"Did you observe that- Minimum element gets add into the result in sacrifice of maximum element.",
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"Still won't able to find pairs? Sort the array and try to find the pattern."
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