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49 lines
2.1 KiB
HTML
49 lines
2.1 KiB
HTML
<p>You are given a string <code>s</code> consisting of lowercase English letters. Your task is to find the <strong>maximum</strong> difference between the frequency of <strong>two</strong> characters in the string such that:</p>
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<ul>
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<li>One of the characters has an <strong>even frequency</strong> in the string.</li>
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<li>The other character has an <strong>odd frequency</strong> in the string.</li>
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</ul>
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<p>Return the <strong>maximum</strong> difference, calculated as the frequency of the character with an <b>odd</b> frequency <strong>minus</strong> the frequency of the character with an <b>even</b> frequency.</p>
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<p> </p>
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<p><strong class="example">Example 1:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">s = "aaaaabbc"</span></p>
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<p><strong>Output:</strong> 3</p>
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<p><strong>Explanation:</strong></p>
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<ul>
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<li>The character <code>'a'</code> has an <strong>odd frequency</strong> of <code><font face="monospace">5</font></code><font face="monospace">,</font> and <code>'b'</code> has an <strong>even frequency</strong> of <code><font face="monospace">2</font></code>.</li>
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<li>The maximum difference is <code>5 - 2 = 3</code>.</li>
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</ul>
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</div>
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<p><strong class="example">Example 2:</strong></p>
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<div class="example-block">
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<p><strong>Input:</strong> <span class="example-io">s = "abcabcab"</span></p>
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<p><strong>Output:</strong> 1</p>
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<p><strong>Explanation:</strong></p>
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<ul>
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<li>The character <code>'a'</code> has an <strong>odd frequency</strong> of <code><font face="monospace">3</font></code><font face="monospace">,</font> and <code>'c'</code> has an <strong>even frequency</strong> of <font face="monospace">2</font>.</li>
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<li>The maximum difference is <code>3 - 2 = 1</code>.</li>
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</ul>
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</div>
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<p> </p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li><code>3 <= s.length <= 100</code></li>
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<li><code>s</code> consists only of lowercase English letters.</li>
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<li><code>s</code> contains at least one character with an odd frequency and one with an even frequency.</li>
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</ul>
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