leetcode-problemset/leetcode-cn/originData/maximum-amount-of-money-robot-can-earn.json

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        "question": {
            "questionId": "3677",
            "questionFrontendId": "3418",
            "categoryTitle": "Algorithms",
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            "title": "Maximum Amount of Money Robot Can Earn",
            "titleSlug": "maximum-amount-of-money-robot-can-earn",
            "content": "<p>You are given an <code>m x n</code> grid. A robot starts at the top-left corner of the grid <code>(0, 0)</code> and wants to reach the bottom-right corner <code>(m - 1, n - 1)</code>. The robot can move either right or down at any point in time.</p>\n\n<p>The grid contains a value <code>coins[i][j]</code> in each cell:</p>\n\n<ul>\n\t<li>If <code>coins[i][j] &gt;= 0</code>, the robot gains that many coins.</li>\n\t<li>If <code>coins[i][j] &lt; 0</code>, the robot encounters a robber, and the robber steals the <strong>absolute</strong> value of <code>coins[i][j]</code> coins.</li>\n</ul>\n\n<p>The robot has a special ability to <strong>neutralize robbers</strong> in at most <strong>2 cells</strong> on its path, preventing them from stealing coins in those cells.</p>\n\n<p><strong>Note:</strong> The robot&#39;s total coins can be negative.</p>\n\n<p>Return the <strong>maximum</strong> profit the robot can gain on the route.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">coins = [[0,1,-1],[1,-2,3],[2,-3,4]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">8</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>An optimal path for maximum coins is:</p>\n\n<ol>\n\t<li>Start at <code>(0, 0)</code> with <code>0</code> coins (total coins = <code>0</code>).</li>\n\t<li>Move to <code>(0, 1)</code>, gaining <code>1</code> coin (total coins = <code>0 + 1 = 1</code>).</li>\n\t<li>Move to <code>(1, 1)</code>, where there&#39;s a robber stealing <code>2</code> coins. The robot uses one neutralization here, avoiding the robbery (total coins = <code>1</code>).</li>\n\t<li>Move to <code>(1, 2)</code>, gaining <code>3</code> coins (total coins = <code>1 + 3 = 4</code>).</li>\n\t<li>Move to <code>(2, 2)</code>, gaining <code>4</code> coins (total coins = <code>4 + 4 = 8</code>).</li>\n</ol>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">coins = [[10,10,10],[10,10,10]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">40</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>An optimal path for maximum coins is:</p>\n\n<ol>\n\t<li>Start at <code>(0, 0)</code> with <code>10</code> coins (total coins = <code>10</code>).</li>\n\t<li>Move to <code>(0, 1)</code>, gaining <code>10</code> coins (total coins = <code>10 + 10 = 20</code>).</li>\n\t<li>Move to <code>(0, 2)</code>, gaining another <code>10</code> coins (total coins = <code>20 + 10 = 30</code>).</li>\n\t<li>Move to <code>(1, 2)</code>, gaining the final <code>10</code> coins (total coins = <code>30 + 10 = 40</code>).</li>\n</ol>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == coins.length</code></li>\n\t<li><code>n == coins[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 500</code></li>\n\t<li><code>-1000 &lt;= coins[i][j] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "机器人可以获得的最大金币数",
            "translatedContent": "<p>给你一个 <code>m x n</code> 的网格。一个机器人从网格的左上角 <code>(0, 0)</code> 出发，目标是到达网格的右下角 <code>(m - 1, n - 1)</code>。在任意时刻，机器人只能向右或向下移动。</p>\n\n<p>网格中的每个单元格包含一个值 <code>coins[i][j]</code>：</p>\n\n<ul>\n\t<li>如果 <code>coins[i][j] &gt;= 0</code>，机器人可以获得该单元格的金币。</li>\n\t<li>如果 <code>coins[i][j] &lt; 0</code>，机器人会遇到一个强盗，强盗会抢走该单元格数值的&nbsp;<strong>绝对值</strong> 的金币。</li>\n</ul>\n\n<p>机器人有一项特殊能力，可以在行程中&nbsp;<strong>最多感化&nbsp;</strong>2个单元格的强盗，从而防止这些单元格的金币被抢走。</p>\n\n<p><strong>注意：</strong>机器人的总金币数可以是负数。</p>\n\n<p>返回机器人在路径上可以获得的&nbsp;<strong>最大金币数&nbsp;</strong>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">coins = [[0,1,-1],[1,-2,3],[2,-3,4]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">8</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>一个获得最多金币的最优路径如下：</p>\n\n<ol>\n\t<li>从 <code>(0, 0)</code> 出发，初始金币为 <code>0</code>（总金币 = <code>0</code>）。</li>\n\t<li>移动到 <code>(0, 1)</code>，获得 <code>1</code> 枚金币（总金币 = <code>0 + 1 = 1</code>）。</li>\n\t<li>移动到 <code>(1, 1)</code>，遇到强盗抢走 <code>2</code> 枚金币。机器人在此处使用一次感化能力，避免被抢（总金币 = <code>1</code>）。</li>\n\t<li>移动到 <code>(1, 2)</code>，获得 <code>3</code> 枚金币（总金币 = <code>1 + 3 = 4</code>）。</li>\n\t<li>移动到 <code>(2, 2)</code>，获得 <code>4</code> 枚金币（总金币 = <code>4 + 4 = 8</code>）。</li>\n</ol>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">coins = [[10,10,10],[10,10,10]]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">40</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>一个获得最多金币的最优路径如下：</p>\n\n<ol>\n\t<li>从 <code>(0, 0)</code> 出发，初始金币为 <code>10</code>（总金币 = <code>10</code>）。</li>\n\t<li>移动到 <code>(0, 1)</code>，获得 <code>10</code> 枚金币（总金币 = <code>10 + 10 = 20</code>）。</li>\n\t<li>移动到 <code>(0, 2)</code>，再获得 <code>10</code> 枚金币（总金币 = <code>20 + 10 = 30</code>）。</li>\n\t<li>移动到 <code>(1, 2)</code>，获得 <code>10</code> 枚金币（总金币 = <code>30 + 10 = 40</code>）。</li>\n</ol>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == coins.length</code></li>\n\t<li><code>n == coins[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 500</code></li>\n\t<li><code>-1000 &lt;= coins[i][j] &lt;= 1000</code></li>\n</ul>\n",
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\\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.11<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u4f7f\\u7528\\u7684\\u662f JetBrains \\u63d0\\u4f9b\\u7684 experimental compiler\\u3002\\u5982\\u679c\\u60a8\\u8ba4\\u4e3a\\u60a8\\u9047\\u5230\\u4e86\\u7f16\\u8bd1\\u5668\\u76f8\\u5173\\u7684\\u95ee\\u9898\\uff0c\\u8bf7\\u5411\\u6211\\u4eec\\u53cd\\u9988<\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.79.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.1.6<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a>\\uff0c<a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/deque\\/tree\\/v1.0.4\\\" target=\\\"_blank\\\"> datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.17 with Erlang\\/OTP 26\"],\"dart\":[\"Dart\",\"<p>Dart 3.2\\u3002\\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/pub.dev\\/packages\\/collection\\/versions\\/1.18.0\\\" target=\\\"_blank\\\">collection<\\/a> \\u5305<\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5c06\\u4f1a\\u88ab\\u4e0d\\u7f16\\u8bd1\\u76f4\\u63a5\\u8fd0\\u884c<\\/p>\"],\"cangjie\":[\"Cangjie\",\"<p>\\u7248\\u672c\\uff1a0.53.11 (cjnative)<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u53c2\\u6570\\uff1a<code>-O2 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