leetcode-problemset/leetcode-cn/originData/fruits-into-baskets-ii.json

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            "questionId": "3790",
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            "title": "Fruits Into Baskets II",
            "titleSlug": "fruits-into-baskets-ii",
            "content": "<p>You are given two arrays of integers, <code>fruits</code> and <code>baskets</code>, each of length <code>n</code>, where <code>fruits[i]</code> represents the <strong>quantity</strong> of the <code>i<sup>th</sup></code> type of fruit, and <code>baskets[j]</code> represents the <strong>capacity</strong> of the <code>j<sup>th</sup></code> basket.</p>\n\n<p>From left to right, place the fruits according to these rules:</p>\n\n<ul>\n\t<li>Each fruit type must be placed in the <strong>leftmost available basket</strong> with a capacity <strong>greater than or equal</strong> to the quantity of that fruit type.</li>\n\t<li>Each basket can hold <b>only one</b> type of fruit.</li>\n\t<li>If a fruit type <b>cannot be placed</b> in any basket, it remains <b>unplaced</b>.</li>\n</ul>\n\n<p>Return the number of fruit types that remain unplaced after all possible allocations are made.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">fruits = [4,2,5], baskets = [3,5,4]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li><code>fruits[0] = 4</code> is placed in <code>baskets[1] = 5</code>.</li>\n\t<li><code>fruits[1] = 2</code> is placed in <code>baskets[0] = 3</code>.</li>\n\t<li><code>fruits[2] = 5</code> cannot be placed in <code>baskets[2] = 4</code>.</li>\n</ul>\n\n<p>Since one fruit type remains unplaced, we return 1.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">fruits = [3,6,1], baskets = [6,4,7]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li><code>fruits[0] = 3</code> is placed in <code>baskets[0] = 6</code>.</li>\n\t<li><code>fruits[1] = 6</code> cannot be placed in <code>baskets[1] = 4</code> (insufficient capacity) but can be placed in the next available basket, <code>baskets[2] = 7</code>.</li>\n\t<li><code>fruits[2] = 1</code> is placed in <code>baskets[1] = 4</code>.</li>\n</ul>\n\n<p>Since all fruits are successfully placed, we return 0.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == fruits.length == baskets.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>1 &lt;= fruits[i], baskets[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "将水果放入篮子 II",
            "translatedContent": "<p>给你两个长度为 <code>n</code>&nbsp;的整数数组，<code>fruits</code> 和 <code>baskets</code>，其中 <code>fruits[i]</code> 表示第 <code>i</code>&nbsp;种水果的 <strong>数量</strong>，<code>baskets[j]</code> 表示第 <code>j</code>&nbsp;个篮子的 <strong>容量</strong>。</p>\n\n<p>你需要对 <code>fruits</code> 数组从左到右按照以下规则放置水果：</p>\n\n<ul>\n\t<li>每种水果必须放入第一个 <strong>容量大于等于</strong> 该水果数量的 <strong>最左侧可用篮子</strong> 中。</li>\n\t<li>每个篮子只能装 <b>一种</b> 水果。</li>\n\t<li>如果一种水果 <b>无法放入</b> 任何篮子，它将保持 <b>未放置</b>。</li>\n</ul>\n\n<p>返回所有可能分配完成后，剩余未放置的水果种类的数量。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">fruits = [4,2,5], baskets = [3,5,4]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li><code>fruits[0] = 4</code> 放入 <code>baskets[1] = 5</code>。</li>\n\t<li><code>fruits[1] = 2</code> 放入 <code>baskets[0] = 3</code>。</li>\n\t<li><code>fruits[2] = 5</code> 无法放入 <code>baskets[2] = 4</code>。</li>\n</ul>\n\n<p>由于有一种水果未放置，我们返回 1。</p>\n</div>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">fruits = [3,6,1], baskets = [6,4,7]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li><code>fruits[0] = 3</code> 放入 <code>baskets[0] = 6</code>。</li>\n\t<li><code>fruits[1] = 6</code> 无法放入 <code>baskets[1] = 4</code>（容量不足），但可以放入下一个可用的篮子 <code>baskets[2] = 7</code>。</li>\n\t<li><code>fruits[2] = 1</code> 放入 <code>baskets[1] = 4</code>。</li>\n</ul>\n\n<p>由于所有水果都已成功放置，我们返回 0。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>n == fruits.length == baskets.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>1 &lt;= fruits[i], baskets[i] &lt;= 1000</code></li>\n</ul>\n",
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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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