mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
199 lines
20 KiB
JSON
199 lines
20 KiB
JSON
{
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"questionId": "1000371",
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"questionFrontendId": "LCP 42",
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"title": "玩具套圈",
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"translatedTitle": "玩具套圈",
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"translatedContent": "「力扣挑战赛」场地外，小力组织了一个套玩具的游戏。所有的玩具摆在平地上，`toys[i]` 以 `[xi,yi,ri]` 的形式记录了第 `i` 个玩具的坐标 `(xi,yi)` 和半径 `ri`。小扣试玩了一下，他扔了若干个半径均为 `r` 的圈，`circles[j]` 记录了第 `j` 个圈的坐标 `(xj,yj)`。套圈的规则如下：\n- 若一个玩具被某个圈完整覆盖了（即玩具的任意部分均在圈内或者圈上），则该玩具被套中。\n- 若一个玩具被多个圈同时套中，最终仅计算为套中一个玩具\n\n请帮助小扣计算，他成功套中了多少玩具。\n\n**注意：**\n- 输入数据保证任意两个玩具的圆心不会重合，但玩具之间可能存在重叠。\n\n\n**示例 1：**\n\n> 输入：`toys = [[3,3,1],[3,2,1]], circles = [[4,3]], r = 2`\n>\n> 输出：`1`\n> \n> 解释： 如图所示，仅套中一个玩具\n\n\n\n**示例 2：**\n\n> 输入：`toys = [[1,3,2],[4,3,1],[7,1,2]], circles = [[1,0],[3,3]], r = 4`\n>\n> 输出：`2`\n> \n> 解释： 如图所示，套中两个玩具\n{:width=\"400px\"}\n\n\n\n**提示：** \n- `1 <= toys.length <= 10^4`\n- `0 <= toys[i][0], toys[i][1] <= 10^9`\n- `1 <= circles.length <= 10^4`\n- `0 <= circles[i][0], circles[i][1] <= 10^9`\n- `1 <= toys[i][2], r <= 10`\n",
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"code": "class Solution {\npublic:\n int circleGame(vector<vector<int>>& toys, vector<vector<int>>& circles, int r) {\n\n }\n};",
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"code": "class Solution(object):\n def circleGame(self, toys, circles, r):\n \"\"\"\n :type toys: List[List[int]]\n :type circles: List[List[int]]\n :type r: int\n :rtype: int\n \"\"\"",
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"code": "/**\n * @param {number[][]} toys\n * @param {number[][]} circles\n * @param {number} r\n * @return {number}\n */\nvar circleGame = function(toys, circles, r) {\n\n};",
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"code": "# @param {Integer[][]} toys\n# @param {Integer[][]} circles\n# @param {Integer} r\n# @return {Integer}\ndef circle_game(toys, circles, r)\n\nend",
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"code": "class Solution {\n func circleGame(_ toys: [[Int]], _ circles: [[Int]], _ r: Int) -> Int {\n\n }\n}",
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