leetcode-problemset/leetcode-cn/originData/total-appeal-of-a-string.json

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    "data": {
        "question": {
            "questionId": "2340",
            "questionFrontendId": "2262",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1457052,
            "title": "Total Appeal of A String",
            "titleSlug": "total-appeal-of-a-string",
            "content": "<p>The <b>appeal</b> of a string is the number of <strong>distinct</strong> characters found in the string.</p>\n\n<ul>\n\t<li>For example, the appeal of <code>&quot;abbca&quot;</code> is <code>3</code> because it has <code>3</code> distinct characters: <code>&#39;a&#39;</code>, <code>&#39;b&#39;</code>, and <code>&#39;c&#39;</code>.</li>\n</ul>\n\n<p>Given a string <code>s</code>, return <em>the <strong>total appeal of all of its <strong>substrings</strong>.</strong></em></p>\n\n<p>A <strong>substring</strong> is a contiguous sequence of characters within a string.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abbca&quot;\n<strong>Output:</strong> 28\n<strong>Explanation:</strong> The following are the substrings of &quot;abbca&quot;:\n- Substrings of length 1: &quot;a&quot;, &quot;b&quot;, &quot;b&quot;, &quot;c&quot;, &quot;a&quot; have an appeal of 1, 1, 1, 1, and 1 respectively. The sum is 5.\n- Substrings of length 2: &quot;ab&quot;, &quot;bb&quot;, &quot;bc&quot;, &quot;ca&quot; have an appeal of 2, 1, 2, and 2 respectively. The sum is 7.\n- Substrings of length 3: &quot;abb&quot;, &quot;bbc&quot;, &quot;bca&quot; have an appeal of 2, 2, and 3 respectively. The sum is 7.\n- Substrings of length 4: &quot;abbc&quot;, &quot;bbca&quot; have an appeal of 3 and 3 respectively. The sum is 6.\n- Substrings of length 5: &quot;abbca&quot; has an appeal of 3. The sum is 3.\nThe total sum is 5 + 7 + 7 + 6 + 3 = 28.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;code&quot;\n<strong>Output:</strong> 20\n<strong>Explanation:</strong> The following are the substrings of &quot;code&quot;:\n- Substrings of length 1: &quot;c&quot;, &quot;o&quot;, &quot;d&quot;, &quot;e&quot; have an appeal of 1, 1, 1, and 1 respectively. The sum is 4.\n- Substrings of length 2: &quot;co&quot;, &quot;od&quot;, &quot;de&quot; have an appeal of 2, 2, and 2 respectively. The sum is 6.\n- Substrings of length 3: &quot;cod&quot;, &quot;ode&quot; have an appeal of 3 and 3 respectively. The sum is 6.\n- Substrings of length 4: &quot;code&quot; has an appeal of 4. The sum is 4.\nThe total sum is 4 + 6 + 6 + 4 = 20.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "字符串的总引力",
            "translatedContent": "<p>字符串的 <strong>引力</strong> 定义为：字符串中 <strong>不同</strong> 字符的数量。</p>\n\n<ul>\n\t<li>例如，<code>\"abbca\"</code> 的引力为 <code>3</code> ，因为其中有 <code>3</code> 个不同字符 <code>'a'</code>、<code>'b'</code> 和 <code>'c'</code> 。</li>\n</ul>\n\n<p>给你一个字符串 <code>s</code> ，返回 <strong>其所有子字符串的总引力</strong> <strong>。</strong></p>\n\n<p><strong>子字符串</strong> 定义为：字符串中的一个连续字符序列。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>s = \"abbca\"\n<strong>输出：</strong>28\n<strong>解释：</strong>\"abbca\" 的子字符串有：\n- 长度为 1 的子字符串：\"a\"、\"b\"、\"b\"、\"c\"、\"a\" 的引力分别为 1、1、1、1、1，总和为 5 。\n- 长度为 2 的子字符串：\"ab\"、\"bb\"、\"bc\"、\"ca\" 的引力分别为 2、1、2、2 ，总和为 7 。\n- 长度为 3 的子字符串：\"abb\"、\"bbc\"、\"bca\" 的引力分别为 2、2、3 ，总和为 7 。\n- 长度为 4 的子字符串：\"abbc\"、\"bbca\" 的引力分别为 3、3 ，总和为 6 。\n- 长度为 5 的子字符串：\"abbca\" 的引力为 3 ，总和为 3 。\n引力总和为 5 + 7 + 7 + 6 + 3 = 28 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>s = \"code\"\n<strong>输出：</strong>20\n<strong>解释：</strong>\"code\" 的子字符串有：\n- 长度为 1 的子字符串：\"c\"、\"o\"、\"d\"、\"e\" 的引力分别为 1、1、1、1 ，总和为 4 。\n- 长度为 2 的子字符串：\"co\"、\"od\"、\"de\" 的引力分别为 2、2、2 ，总和为 6 。\n- 长度为 3 的子字符串：\"cod\"、\"ode\" 的引力分别为 3、3 ，总和为 6 。\n- 长度为 4 的子字符串：\"code\" 的引力为 4 ，总和为 4 。\n引力总和为 4 + 6 + 6 + 4 = 20 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 由小写英文字母组成</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    long long appealSum(string s) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def appealSum(self, s):\n        \"\"\"\n        :type s: str\n        :rtype: int\n        \"\"\"",
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                    "code": "public class Solution {\n    public long AppealSum(string s) {\n\n    }\n}",
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                    "code": "/**\n * @param {string} s\n * @return {number}\n */\nvar appealSum = function(s) {\n\n};",
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                    "code": "# @param {String} s\n# @return {Integer}\ndef appeal_sum(s)\n\nend",
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                    "code": "class Solution {\n    func appealSum(_ s: String) -> Int {\n\n    }\n}",
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                    "code": "class Solution {\n    fun appealSum(s: String): Long {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn appeal_sum(s: String) -> i64 {\n\n    }\n}",
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                    "lang": "PHP",
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                    "code": "class Solution {\n\n    /**\n     * @param String $s\n     * @return Integer\n     */\n    function appealSum($s) {\n\n    }\n}",
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                    "code": "defmodule Solution do\n  @spec appeal_sum(s :: String.t) :: integer\n  def appeal_sum(s) do\n\n  end\nend",
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            "hints": [
                "Consider the set of substrings that end at a certain index i. Then, consider a specific alphabetic character. How do you count the number of substrings ending at index i that contain that character?",
                "The number of substrings that contain the alphabetic character is equivalent to 1 plus the index of the last occurrence of the character before index i + 1.",
                "The total appeal of all substrings ending at index i is the total sum of the number of substrings that contain each alphabetic character.",
                "To find the total appeal of all substrings, we simply sum up the total appeal for each index."
            ],
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            "sampleTestCase": "\"abbca\"",
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