leetcode-problemset/leetcode-cn/originData/time-needed-to-rearrange-a-binary-string.json

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            "questionId": "2464",
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            "categoryTitle": "Algorithms",
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            "title": "Time Needed to Rearrange a Binary String",
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            "content": "<p>You are given a binary string <code>s</code>. In one second, <strong>all</strong> occurrences of <code>&quot;01&quot;</code> are <strong>simultaneously</strong> replaced with <code>&quot;10&quot;</code>. This process <strong>repeats</strong> until no occurrences of <code>&quot;01&quot;</code> exist.</p>\n\n<p>Return<em> the number of seconds needed to complete this process.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;0110101&quot;\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> \nAfter one second, s becomes &quot;1011010&quot;.\nAfter another second, s becomes &quot;1101100&quot;.\nAfter the third second, s becomes &quot;1110100&quot;.\nAfter the fourth second, s becomes &quot;1111000&quot;.\nNo occurrence of &quot;01&quot; exists any longer, and the process needed 4 seconds to complete,\nso we return 4.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;11100&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nNo occurrence of &quot;01&quot; exists in s, and the processes needed 0 seconds to complete,\nso we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s[i]</code> is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong></p>\n\n<p>Can you solve this problem in O(n) time complexity?</p>\n",
            "translatedTitle": "二进制字符串重新安排顺序需要的时间",
            "translatedContent": "<p>给你一个二进制字符串&nbsp;<code>s</code>&nbsp;。在一秒之中，<strong>所有</strong>&nbsp;子字符串&nbsp;<code>\"01\"</code> <strong>同时</strong>&nbsp;被替换成&nbsp;<code>\"10\"</code>&nbsp;。这个过程持续进行到没有&nbsp;<code>\"01\"</code>&nbsp;存在。</p>\n\n<p>请你返回完成这个过程所需要的秒数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"0110101\"\n<b>输出：</b>4\n<b>解释：</b>\n一秒后，s 变成 \"1011010\" 。\n再过 1 秒后，s 变成 \"1101100\" 。\n第三秒过后，s 变成 \"1110100\" 。\n第四秒后，s 变成 \"1111000\" 。\n此时没有 \"01\" 存在，整个过程花费 4 秒。\n所以我们返回 4 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>s = \"11100\"\n<b>输出：</b>0\n<strong>解释：</strong>\ns 中没有 \"01\" 存在，整个过程花费 0 秒。\n所以我们返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s[i]</code>&nbsp;要么是&nbsp;<code>'0'</code>&nbsp;，要么是&nbsp;<code>'1'</code> 。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong></p>\n\n<p>你能以 O(n) 的时间复杂度解决这个问题吗？</p>\n",
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