mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
21 KiB
JSON
174 lines
21 KiB
JSON
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"questionId": "130",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1889,
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"title": "Surrounded Regions",
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"titleSlug": "surrounded-regions",
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"content": "<p>Given an <code>m x n</code> matrix <code>board</code> containing <code>'X'</code> and <code>'O'</code>, <em>capture all regions that are 4-directionally surrounded by</em> <code>'X'</code>.</p>\n\n<p>A region is <strong>captured</strong> by flipping all <code>'O'</code>s into <code>'X'</code>s in that surrounded region.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/xogrid.jpg\" style=\"width: 550px; height: 237px;\" />\n<pre>\n<strong>Input:</strong> board = [["X","X","X","X"],["X","O","O","X"],["X","X","O","X"],["X","O","X","X"]]\n<strong>Output:</strong> [["X","X","X","X"],["X","X","X","X"],["X","X","X","X"],["X","O","X","X"]]\n<strong>Explanation:</strong> Surrounded regions should not be on the border, which means that any 'O' on the border of the board are not flipped to 'X'. Any 'O' that is not on the border and it is not connected to an 'O' on the border will be flipped to 'X'. Two cells are connected if they are adjacent cells connected horizontally or vertically.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> board = [["X"]]\n<strong>Output:</strong> [["X"]]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 <= m, n <= 200</code></li>\n\t<li><code>board[i][j]</code> is <code>'X'</code> or <code>'O'</code>.</li>\n</ul>\n",
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"translatedTitle": "被围绕的区域",
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"translatedContent": "给你一个 <code>m x n</code> 的矩阵 <code>board</code> ，由若干字符 <code>'X'</code> 和 <code>'O'</code> ，找到所有被 <code>'X'</code> 围绕的区域，并将这些区域里所有的 <code>'O'</code> 用 <code>'X'</code> 填充。\n<div class=\"original__bRMd\">\n<div>\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/xogrid.jpg\" style=\"width: 550px; height: 237px;\" />\n<pre>\n<strong>输入：</strong>board = [[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"O\",\"O\",\"X\"],[\"X\",\"X\",\"O\",\"X\"],[\"X\",\"O\",\"X\",\"X\"]]\n<strong>输出：</strong>[[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"X\",\"X\",\"X\"],[\"X\",\"O\",\"X\",\"X\"]]\n<strong>解释：</strong>被围绕的区间不会存在于边界上，换句话说，任何边界上的 <code>'O'</code> 都不会被填充为 <code>'X'</code>。 任何不在边界上，或不与边界上的 <code>'O'</code> 相连的 <code>'O'</code> 最终都会被填充为 <code>'X'</code>。如果两个元素在水平或垂直方向相邻，则称它们是“相连”的。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>board = [[\"X\"]]\n<strong>输出：</strong>[[\"X\"]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 <= m, n <= 200</code></li>\n\t<li><code>board[i][j]</code> 为 <code>'X'</code> 或 <code>'O'</code></li>\n</ul>\n</div>\n</div>\n",
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