leetcode-problemset/leetcode-cn/originData/palindrome-linked-list-lcci.json

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        "question": {
            "questionId": "100164",
            "questionFrontendId": "面试题 02.06",
            "categoryTitle": "LCCI",
            "boundTopicId": 45650,
            "title": "Palindrome Linked List LCCI",
            "titleSlug": "palindrome-linked-list-lcci",
            "content": "<p>Implement a function to check if a linked list is a palindrome.</p>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><strong>Example 1: </strong></p>\r\n\r\n<pre>\r\n<strong>Input:  </strong>1-&gt;2\r\n<strong>Output: </strong> false \r\n</pre>\r\n\r\n<p><strong>Example 2: </strong></p>\r\n\r\n<pre>\r\n<strong>Input:  </strong>1-&gt;2-&gt;2-&gt;1\r\n<strong>Output: </strong> true \r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><b>Follow up:</b><br />\r\nCould you do it in O(n) time and O(1) space?</p>\r\n",
            "translatedTitle": "回文链表",
            "translatedContent": "<p>编写一个函数，检查输入的链表是否是回文的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入： </strong>1-&gt;2\n<strong>输出：</strong> false \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入： </strong>1-&gt;2-&gt;2-&gt;1\n<strong>输出：</strong> true \n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong><br>\n你能否用 O(n) 时间复杂度和 O(1) 空间复杂度解决此题？</p>\n",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode(int x) : val(x), next(NULL) {}\n * };\n */\nclass Solution {\npublic:\n    bool isPalindrome(ListNode* head) {\n\n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode(int x) { val = x; }\n * }\n */\nclass Solution {\n    public boolean isPalindrome(ListNode head) {\n\n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, x):\n#         self.val = x\n#         self.next = None\nclass Solution(object):\n    def isPalindrome(self, head):\n        \"\"\"\n        :type head: ListNode\n        :rtype: bool\n        \"\"\"",
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                    "code": "# Definition for singly-linked list.\n# class ListNode:\n#     def __init__(self, x):\n#         self.val = x\n#         self.next = None\nclass Solution:\n    def isPalindrome(self, head: ListNode) -> bool:",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\n\n\nbool isPalindrome(struct ListNode* head){\n\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int x) { val = x; }\n * }\n */\npublic class Solution {\n    public bool IsPalindrome(ListNode head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val) {\n *     this.val = val;\n *     this.next = null;\n * }\n */\n/**\n * @param {ListNode} head\n * @return {boolean}\n */\nvar isPalindrome = function(head) {\n\n};",
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                    "code": "# Definition for singly-linked list.\n# class ListNode\n#     attr_accessor :val, :next\n#     def initialize(val)\n#         @val = val\n#         @next = nil\n#     end\n# end\n# @param {ListNode} head\n# @return {Boolean}\ndef is_palindrome(head)\n\nend",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public var val: Int\n *     public var next: ListNode?\n *     public init(_ val: Int) {\n *         self.val = val\n *         self.next = nil\n *     }\n * }\n */\nclass Solution {\n    func isPalindrome(_ head: ListNode?) -> Bool {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc isPalindrome(head *ListNode) bool {\n\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode(var _x: Int = 0) {\n *   var next: ListNode = null\n *   var x: Int = _x\n * }\n */\nobject Solution {\n    def isPalindrome(head: ListNode): Boolean = {\n\n    }\n}",
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                    "code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n *     var next: ListNode? = null\n * }\n */\nclass Solution {\n    fun isPalindrome(head: ListNode?): Boolean {\n\n    }\n}",
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                    "lang": "Rust",
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                    "code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n//   pub val: i32,\n//   pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n//   #[inline]\n//   fn new(val: i32) -> Self {\n//     ListNode {\n//       next: None,\n//       val\n//     }\n//   }\n// }\nimpl Solution {\n    pub fn is_palindrome(head: Option<Box<ListNode>>) -> bool {\n\n    }\n}",
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                    "lang": "PHP",
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                    "code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n *     public $val = 0;\n *     public $next = null;\n *     function __construct($val) { $this->val = $val; }\n * }\n */\nclass Solution {\n\n    /**\n     * @param ListNode $head\n     * @return Boolean\n     */\n    function isPalindrome($head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction isPalindrome(head: ListNode | null): boolean {\n\n};",
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                    "code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n  (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n  (list-node val #f))\n\n|#\n\n(define/contract (is-palindrome head)\n  (-> (or/c list-node? #f) boolean?)\n\n  )",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec is_palindrome(Head :: #list_node{} | null) -> boolean().\nis_palindrome(Head) ->\n  .",
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                    "lang": "Elixir",
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                    "code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n#   @type t :: %__MODULE__{\n#           val: integer,\n#           next: ListNode.t() | nil\n#         }\n#   defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n  @spec is_palindrome(head :: ListNode.t | nil) :: boolean\n  def is_palindrome(head) do\n\n  end\nend",
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            "hints": [
                "回文数在向前写和向后写时是相同的。如果你颠倒链表会怎样？",
                "用栈试试。",
                "假设你有链表的长度。你可以实现这个递归吗？",
                "在递归方法中（我们有链表的长度），中点是基线条件，即isPalindrome(middle)是true。节点x是紧挨着middle的左侧的一个节点：该如何检查x -> middle -> y是否形成回文？现在假设检查通过。前一个节点a又该如何检查？如果x -> middle -> y是回文，怎么检查a -> x -> middle -> y -> b是回文？",
                "回到前面的提示。记住：返回多个值的方法有很多。你可以用一个新类来实现。"
            ],
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