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leetcode-problemset/leetcode-cn/originData/nth-digit.json
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{
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"categoryTitle": "Algorithms",
"boundTopicId": 1672,
"title": "Nth Digit",
"titleSlug": "nth-digit",
"content": "<p>Given an integer <code>n</code>, return the <code>n<sup>th</sup></code> digit of the infinite integer sequence <code>[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...]</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3\n<strong>Output:</strong> 3\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 11\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The 11<sup>th</sup> digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... is a 0, which is part of the number 10.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
"translatedTitle": "第 N 位数字",
"translatedContent": "<p>给你一个整数 <code>n</code> ,请你在无限的整数序列&nbsp;<code>[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...]</code> 中找出并返回第&nbsp;<code>n</code><em> </em>位上的数字。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 3\n<strong>输出:</strong>3\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 11\n<strong>输出:</strong>0\n<strong>解释:</strong>第 11 位数字在序列 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... 里是 <strong>0 </strong>,它是 10 的一部分。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 2<sup>31</sup> - 1</code></li>\n</ul>\n",
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