leetcode-problemset/leetcode-cn/originData/minimize-maximum-of-array.json

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            "title": "Minimize Maximum of Array",
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            "content": "<p>You are given a <strong>0-indexed</strong> array <code>nums</code> comprising of <code>n</code> non-negative integers.</p>\n\n<p>In one operation, you must:</p>\n\n<ul>\n\t<li>Choose an integer <code>i</code> such that <code>1 &lt;= i &lt; n</code> and <code>nums[i] &gt; 0</code>.</li>\n\t<li>Decrease <code>nums[i]</code> by 1.</li>\n\t<li>Increase <code>nums[i - 1]</code> by 1.</li>\n</ul>\n\n<p>Return<em> the <strong>minimum</strong> possible value of the <strong>maximum</strong> integer of </em><code>nums</code><em> after performing <strong>any</strong> number of operations</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,7,1,6]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong>\nOne set of optimal operations is as follows:\n1. Choose i = 1, and nums becomes [4,6,1,6].\n2. Choose i = 3, and nums becomes [4,6,2,5].\n3. Choose i = 1, and nums becomes [5,5,2,5].\nThe maximum integer of nums is 5. It can be shown that the maximum number cannot be less than 5.\nTherefore, we return 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,1]\n<strong>Output:</strong> 10\n<strong>Explanation:</strong>\nIt is optimal to leave nums as is, and since 10 is the maximum value, we return 10.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "最小化数组中的最大值",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的数组&nbsp;<code>nums</code>&nbsp;，它含有&nbsp;<code>n</code>&nbsp;个非负整数。</p>\n\n<p>每一步操作中，你需要：</p>\n\n<ul>\n\t<li>选择一个满足&nbsp;<code>1 &lt;= i &lt; n</code>&nbsp;的整数 <code>i</code>&nbsp;，且&nbsp;<code>nums[i] &gt; 0</code>&nbsp;。</li>\n\t<li>将&nbsp;<code>nums[i]</code>&nbsp;减 1 。</li>\n\t<li>将&nbsp;<code>nums[i - 1]</code>&nbsp;加 1 。</li>\n</ul>\n\n<p>你可以对数组执行 <strong>任意</strong>&nbsp;次上述操作，请你返回可以得到的 <code>nums</code>&nbsp;数组中<b>&nbsp;最大值</b>&nbsp;<strong>最小</strong> 为多少。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [3,7,1,6]\n<b>输出：</b>5\n<strong>解释：</strong>\n一串最优操作是：\n1. 选择 i = 1 ，nums 变为 [4,6,1,6] 。\n2. 选择 i = 3 ，nums 变为 [4,6,2,5] 。\n3. 选择 i = 1 ，nums 变为 [5,5,2,5] 。\nnums 中最大值为 5 。无法得到比 5 更小的最大值。\n所以我们返回 5 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [10,1]\n<b>输出：</b>10\n<strong>解释：</strong>\n最优解是不改动 nums ，10 是最大值，所以返回 10 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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