leetcode-problemset/leetcode-cn/originData/merge-triplets-to-form-target-triplet.json

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        "question": {
            "questionId": "2026",
            "questionFrontendId": "1899",
            "categoryTitle": "Algorithms",
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            "title": "Merge Triplets to Form Target Triplet",
            "titleSlug": "merge-triplets-to-form-target-triplet",
            "content": "<p>A <strong>triplet</strong> is an array of three integers. You are given a 2D integer array <code>triplets</code>, where <code>triplets[i] = [a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>]</code> describes the <code>i<sup>th</sup></code> <strong>triplet</strong>. You are also given an integer array <code>target = [x, y, z]</code> that describes the <strong>triplet</strong> you want to obtain.</p>\n\n<p>To obtain <code>target</code>, you may apply the following operation on <code>triplets</code> <strong>any number</strong> of times (possibly <strong>zero</strong>):</p>\n\n<ul>\n\t<li>Choose two indices (<strong>0-indexed</strong>) <code>i</code> and <code>j</code> (<code>i != j</code>) and <strong>update</strong> <code>triplets[j]</code> to become <code>[max(a<sub>i</sub>, a<sub>j</sub>), max(b<sub>i</sub>, b<sub>j</sub>), max(c<sub>i</sub>, c<sub>j</sub>)]</code>.\n\n\t<ul>\n\t\t<li>For example, if <code>triplets[i] = [2, 5, 3]</code> and <code>triplets[j] = [1, 7, 5]</code>, <code>triplets[j]</code> will be updated to <code>[max(2, 1), max(5, 7), max(3, 5)] = [2, 7, 5]</code>.</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>Return <code>true</code> <em>if it is possible to obtain the </em><code>target</code><em> <strong>triplet</strong> </em><code>[x, y, z]</code><em> as an<strong> element</strong> of </em><code>triplets</code><em>, or </em><code>false</code><em> otherwise</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> triplets = [[2,5,3],[1,8,4],[1,7,5]], target = [2,7,5]\n<strong>Output:</strong> true\n<strong>Explanation:</strong> Perform the following operations:\n- Choose the first and last triplets [<u>[2,5,3]</u>,[1,8,4],<u>[1,7,5]</u>]. Update the last triplet to be [max(2,1), max(5,7), max(3,5)] = [2,7,5]. triplets = [[2,5,3],[1,8,4],<u>[2,7,5]</u>]\nThe target triplet [2,7,5] is now an element of triplets.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> triplets = [[3,4,5],[4,5,6]], target = [3,2,5]\n<strong>Output:</strong> false\n<strong>Explanation:</strong> It is impossible to have [3,2,5] as an element because there is no 2 in any of the triplets.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> triplets = [[2,5,3],[2,3,4],[1,2,5],[5,2,3]], target = [5,5,5]\n<strong>Output:</strong> true\n<strong>Explanation: </strong>Perform the following operations:\n- Choose the first and third triplets [<u>[2,5,3]</u>,[2,3,4],<u>[1,2,5]</u>,[5,2,3]]. Update the third triplet to be [max(2,1), max(5,2), max(3,5)] = [2,5,5]. triplets = [[2,5,3],[2,3,4],<u>[2,5,5]</u>,[5,2,3]].\n- Choose the third and fourth triplets [[2,5,3],[2,3,4],<u>[2,5,5]</u>,<u>[5,2,3]</u>]. Update the fourth triplet to be [max(2,5), max(5,2), max(5,3)] = [5,5,5]. triplets = [[2,5,3],[2,3,4],[2,5,5],<u>[5,5,5]</u>].\nThe target triplet [5,5,5] is now an element of triplets.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= triplets.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>triplets[i].length == target.length == 3</code></li>\n\t<li><code>1 &lt;= a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, x, y, z &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "合并若干三元组以形成目标三元组",
            "translatedContent": "<p><strong>三元组</strong> 是一个由三个整数组成的数组。给你一个二维整数数组 <code>triplets</code> ，其中 <code>triplets[i] = [a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>]</code> 表示第 <code>i</code> 个 <strong>三元组</strong> 。同时，给你一个整数数组 <code>target = [x, y, z]</code> ，表示你想要得到的 <strong>三元组</strong> 。</p>\n\n<p>为了得到 <code>target</code> ，你需要对 <code>triplets</code> 执行下面的操作 <strong>任意次</strong>（可能 <strong>零</strong> 次）：</p>\n\n<ul>\n\t<li>选出两个下标（下标 <strong>从 0 开始</strong> 计数）<code>i</code> 和 <code>j</code>（<code>i != j</code>），并 <strong>更新</strong> <code>triplets[j]</code> 为 <code>[max(a<sub>i</sub>, a<sub>j</sub>), max(b<sub>i</sub>, b<sub>j</sub>), max(c<sub>i</sub>, c<sub>j</sub>)]</code> 。\n\n\t<ul>\n\t\t<li>例如，<code>triplets[i] = [2, 5, 3]</code> 且 <code>triplets[j] = [1, 7, 5]</code>，<code>triplets[j]</code> 将会更新为 <code>[max(2, 1), max(5, 7), max(3, 5)] = [2, 7, 5]</code> 。</li>\n\t</ul>\n\t</li>\n</ul>\n\n<p>如果通过以上操作我们可以使得目标 <strong>三元组</strong> <code>target</code> 成为 <code>triplets</code> 的一个 <strong>元素</strong> ，则返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>triplets = [[2,5,3],[1,8,4],[1,7,5]], target = [2,7,5]\n<strong>输出：</strong>true\n<strong>解释：</strong>执行下述操作：\n- 选择第一个和最后一个三元组 [<strong>[2,5,3]</strong>,[1,8,4],<strong>[1,7,5]</strong>] 。更新最后一个三元组为 [max(2,1), max(5,7), max(3,5)] = [2,7,5] 。triplets = [[2,5,3],[1,8,4],<strong>[2,7,5]</strong>]\n目标三元组 [2,7,5] 现在是 triplets 的一个元素。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>triplets = [[1,3,4],[2,5,8]], target = [2,5,8]\n<strong>输出：</strong>true\n<strong>解释：</strong>目标三元组 [2,5,8] 已经是 triplets 的一个元素。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>triplets = [[2,5,3],[2,3,4],[1,2,5],[5,2,3]], target = [5,5,5]\n<strong>输出：</strong>true\n<strong>解释：</strong>执行下述操作：\n- 选择第一个和第三个三元组 [<strong>[2,5,3]</strong>,[2,3,4],<strong>[1,2,5]</strong>,[5,2,3]] 。更新第三个三元组为 [max(2,1), max(5,2), max(3,5)] = [2,5,5] 。triplets = [[2,5,3],[2,3,4],<strong>[2,5,5]</strong>,[5,2,3]] 。\n- 选择第三个和第四个三元组 [[2,5,3],[2,3,4],<strong>[2,5,5]</strong>,<strong>[5,2,3]</strong>] 。更新第四个三元组为 [max(2,5), max(5,2), max(5,3)] = [5,5,5] 。triplets = [[2,5,3],[2,3,4],[2,5,5],<strong>[5,5,5]</strong>] 。\n目标三元组 [5,5,5] 现在是 triplets 的一个元素。\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>triplets = [[3,4,5],[4,5,6]], target = [3,2,5]\n<strong>输出：</strong>false\n<strong>解释：</strong>无法得到 [3,2,5] ，因为 triplets 不含 2 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= triplets.length <= 10<sup>5</sup></code></li>\n\t<li><code>triplets[i].length == target.length == 3</code></li>\n\t<li><code>1 <= a<sub>i</sub>, b<sub>i</sub>, c<sub>i</sub>, x, y, z <= 1000</code></li>\n</ul>\n",
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href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\\" target=\\\"_blank\\\"> datastructures-js\\/queue<\\/a>\\u3002<\\/p>\"],\"ruby\":[\"Ruby\",\"<p>\\u4f7f\\u7528<code>Ruby 3.1<\\/code>\\u6267\\u884c<\\/p>\\r\\n\\r\\n<p>\\u4e00\\u4e9b\\u5e38\\u7528\\u7684\\u6570\\u636e\\u7ed3\\u6784\\u5df2\\u5728 Algorithms \\u6a21\\u5757\\u4e2d\\u63d0\\u4f9b\\uff1ahttps:\\/\\/www.rubydoc.info\\/github\\/kanwei\\/algorithms\\/Algorithms<\\/p>\"],\"swift\":[\"Swift\",\"<p>\\u7248\\u672c\\uff1a<code>Swift 5.5.2<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u901a\\u5e38\\u4fdd\\u8bc1\\u66f4\\u65b0\\u5230 <a href=\\\"https:\\/\\/swift.org\\/download\\/\\\" target=\\\"_blank\\\">Apple\\u653e\\u51fa\\u7684\\u6700\\u65b0\\u7248Swift<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u53d1\\u73b0Swift\\u4e0d\\u662f\\u6700\\u65b0\\u7248\\u7684\\uff0c\\u8bf7\\u8054\\u7cfb\\u6211\\u4eec\\uff01\\u6211\\u4eec\\u5c06\\u5c3d\\u5feb\\u66f4\\u65b0\\u3002<\\/p>\"],\"golang\":[\"Go\",\"<p>\\u7248\\u672c\\uff1a<code>Go 1.17<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 <a href=\\\"https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap \\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"http:\\/\\/www.grantjenks.com\\/docs\\/sortedcontainers\\/\\\" target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 2.13<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.3.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 4.5.4<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2020<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.3<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 24.2\"],\"elixir\":[\"Elixir\",\"Elixir 1.13.0 with Erlang\\/OTP 24.2\"]}",
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