leetcode-problemset/leetcode-cn/originData/maximum-sum-of-two-non-overlapping-subarrays.json

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            "title": "Maximum Sum of Two Non-Overlapping Subarrays",
            "titleSlug": "maximum-sum-of-two-non-overlapping-subarrays",
            "content": "<p>Given an integer array <code>nums</code> and two integers <code>firstLen</code> and <code>secondLen</code>, return <em>the maximum sum of elements in two non-overlapping <strong>subarrays</strong> with lengths </em><code>firstLen</code><em> and </em><code>secondLen</code>.</p>\n\n<p>The array with length <code>firstLen</code> could occur before or after the array with length <code>secondLen</code>, but they have to be non-overlapping.</p>\n\n<p>A <strong>subarray</strong> is a <strong>contiguous</strong> part of an array.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [0,6,5,2,2,5,1,9,4], firstLen = 1, secondLen = 2\n<strong>Output:</strong> 20\n<strong>Explanation:</strong> One choice of subarrays is [9] with length 1, and [6,5] with length 2.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,8,1,3,2,1,8,9,0], firstLen = 3, secondLen = 2\n<strong>Output:</strong> 29\n<strong>Explanation:</strong> One choice of subarrays is [3,8,1] with length 3, and [8,9] with length 2.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,1,5,6,0,9,5,0,3,8], firstLen = 4, secondLen = 3\n<strong>Output:</strong> 31\n<strong>Explanation:</strong> One choice of subarrays is [5,6,0,9] with length 4, and [0,3,8] with length 3.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= firstLen, secondLen &lt;= 1000</code></li>\n\t<li><code>2 &lt;= firstLen + secondLen &lt;= 1000</code></li>\n\t<li><code>firstLen + secondLen &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "两个非重叠子数组的最大和",
            "translatedContent": "<p>给出非负整数数组 <code>A</code> ，返回两个非重叠（连续）子数组中元素的最大和，子数组的长度分别为 <code>L</code> 和 <code>M</code>。（这里需要澄清的是，长为 L 的子数组可以出现在长为 M 的子数组之前或之后。）</p>\n\n<p>从形式上看，返回最大的 <code>V</code>，而 <code>V = (A[i] + A[i+1] + ... + A[i+L-1]) + (A[j] + A[j+1] + ... + A[j+M-1])</code> 并满足下列条件之一：</p>\n\n<p>&nbsp;</p>\n\n<ul>\n\t<li><code>0 &lt;= i &lt; i + L - 1 &lt; j &lt; j + M - 1 &lt; A.length</code>, <strong>或</strong></li>\n\t<li><code>0 &lt;= j &lt; j + M - 1 &lt; i &lt; i + L - 1 &lt; A.length</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>A = [0,6,5,2,2,5,1,9,4], L = 1, M = 2\n<strong>输出：</strong>20\n<strong>解释：</strong>子数组的一种选择中，[9] 长度为 1，[6,5] 长度为 2。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>A = [3,8,1,3,2,1,8,9,0], L = 3, M = 2\n<strong>输出：</strong>29\n<strong>解释：</strong>子数组的一种选择中，[3,8,1] 长度为 3，[8,9] 长度为 2。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>A = [2,1,5,6,0,9,5,0,3,8], L = 4, M = 3\n<strong>输出：</strong>31\n<strong>解释：</strong>子数组的一种选择中，[5,6,0,9] 长度为 4，[0,3,8] 长度为 3。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>L &gt;= 1</code></li>\n\t<li><code>M &gt;= 1</code></li>\n\t<li><code>L + M &lt;= A.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= A[i] &lt;= 1000</code></li>\n</ul>\n",
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