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leetcode-problemset/leetcode-cn/originData/jian-sheng-zi-ii-lcof.json
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"question": {
"questionId": "100285",
"questionFrontendId": "剑指 Offer 14- II",
"categoryTitle": "LCOF",
"boundTopicId": 85544,
"title": "剪绳子 II LCOF",
"titleSlug": "jian-sheng-zi-ii-lcof",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "剪绳子 II",
"translatedContent": "<p>给你一根长度为 <code>n</code> 的绳子,请把绳子剪成整数长度的 <code>m</code>&nbsp;段m、n都是整数n&gt;1并且m&gt;1每段绳子的长度记为 <code>k[0],k[1]...k[m - 1]</code> 。请问 <code>k[0]*k[1]*...*k[m - 1]</code> 可能的最大乘积是多少例如当绳子的长度是8时我们把它剪成长度分别为2、3、3的三段此时得到的最大乘积是18。</p>\n\n<p>答案需要取模 1e9+71000000007如计算初始结果为1000000008请返回 1。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><strong>输入: </strong>2\n<strong>输出: </strong>1\n<strong>解释: </strong>2 = 1 + 1, 1 &times; 1 = 1</pre>\n\n<p><strong>示例&nbsp;2:</strong></p>\n\n<pre><strong>输入: </strong>10\n<strong>输出: </strong>36\n<strong>解释: </strong>10 = 3 + 3 + 4, 3 &times;&nbsp;3 &times;&nbsp;4 = 36</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 1000</code></li>\n</ul>\n\n<p>注意:本题与主站 343 题相同:<a href=\"https://leetcode-cn.com/problems/integer-break/\">https://leetcode-cn.com/problems/integer-break/</a></p>\n",
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