leetcode-problemset/leetcode-cn/originData/fraction-to-recurring-decimal.json

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        "question": {
            "questionId": "166",
            "questionFrontendId": "166",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1765,
            "title": "Fraction to Recurring Decimal",
            "titleSlug": "fraction-to-recurring-decimal",
            "content": "<p>Given two integers representing the <code>numerator</code> and <code>denominator</code> of a fraction, return <em>the fraction in string format</em>.</p>\n\n<p>If the fractional part is repeating, enclose the repeating part in parentheses.</p>\n\n<p>If multiple answers are possible, return <strong>any of them</strong>.</p>\n\n<p>It is <strong>guaranteed</strong> that the length of the answer string is less than <code>10<sup>4</sup></code> for all the given inputs.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> numerator = 1, denominator = 2\n<strong>Output:</strong> &quot;0.5&quot;\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> numerator = 2, denominator = 1\n<strong>Output:</strong> &quot;2&quot;\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> numerator = 4, denominator = 333\n<strong>Output:</strong> &quot;0.(012)&quot;\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>-2<sup>31</sup> &lt;=&nbsp;numerator, denominator &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li><code>denominator != 0</code></li>\n</ul>\n",
            "translatedTitle": "分数到小数",
            "translatedContent": "<p>给定两个整数，分别表示分数的分子&nbsp;<code>numerator</code> 和分母 <code>denominator</code>，以 <strong>字符串形式返回小数</strong> 。</p>\n\n<p>如果小数部分为循环小数，则将循环的部分括在括号内。</p>\n\n<p>如果存在多个答案，只需返回 <strong>任意一个</strong> 。</p>\n\n<p>对于所有给定的输入，<strong>保证</strong> 答案字符串的长度小于 <code>10<sup>4</sup></code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>numerator = 1, denominator = 2\n<strong>输出：</strong>\"0.5\"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>numerator = 2, denominator = 1\n<strong>输出：</strong>\"2\"\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>numerator = 4, denominator = 333\n<strong>输出：</strong>\"0.(012)\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>-2<sup>31</sup> &lt;=&nbsp;numerator, denominator &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li><code>denominator != 0</code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    string fractionToDecimal(int numerator, int denominator) {\n\n    }\n};",
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                    "code": "class Solution {\n    public String fractionToDecimal(int numerator, int denominator) {\n\n    }\n}",
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                    "code": "class Solution(object):\n    def fractionToDecimal(self, numerator, denominator):\n        \"\"\"\n        :type numerator: int\n        :type denominator: int\n        :rtype: str\n        \"\"\"",
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                    "code": "/**\n * @param {number} numerator\n * @param {number} denominator\n * @return {string}\n */\nvar fractionToDecimal = function(numerator, denominator) {\n\n};",
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                    "code": "# @param {Integer} numerator\n# @param {Integer} denominator\n# @return {String}\ndef fraction_to_decimal(numerator, denominator)\n\nend",
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                    "code": "class Solution {\n    func fractionToDecimal(_ numerator: Int, _ denominator: Int) -> String {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn fraction_to_decimal(numerator: i32, denominator: i32) -> String {\n\n    }\n}",
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                    "code": "-spec fraction_to_decimal(Numerator :: integer(), Denominator :: integer()) -> unicode:unicode_binary().\nfraction_to_decimal(Numerator, Denominator) ->\n  .",
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            "hints": [
                "No scary math, just apply elementary math knowledge. Still remember how to perform a <i>long division</i>?",
                "Try a long division on 4/9, the repeating part is obvious. Now try 4/333. Do you see a pattern?",
                "Notice that once the remainder starts repeating, so does the divided result.",
                "Be wary of edge cases! List out as many test cases as you can think of and test your code thoroughly."
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