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leetcode-problemset/leetcode-cn/originData/er-cha-shu-zhong-he-wei-mou-yi-zhi-de-lu-jing-lcof.json
2022-05-02 23:44:12 +08:00

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{
"data": {
"question": {
"questionId": "100317",
"questionFrontendId": "剑指 Offer 34",
"categoryTitle": "LCOF",
"boundTopicId": 87252,
"title": "二叉树中和为某一值的路径 LCOF",
"titleSlug": "er-cha-shu-zhong-he-wei-mou-yi-zhi-de-lu-jing-lcof",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "二叉树中和为某一值的路径",
"translatedContent": "<p>给你二叉树的根节点 <code>root</code> 和一个整数目标和 <code>targetSum</code> ,找出所有 <strong>从根节点到叶子节点</strong> 路径总和等于给定目标和的路径。</p>\n\n<p><strong>叶子节点</strong> 是指没有子节点的节点。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/18/pathsumii1.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong>root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22\n<strong>输出:</strong>[[5,4,11,2],[5,8,4,5]]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/18/pathsum2.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong>root = [1,2,3], targetSum = 5\n<strong>输出:</strong>[]\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [1,2], targetSum = 0\n<strong>输出:</strong>[]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中节点总数在范围 <code>[0, 5000]</code> 内</li>\n\t<li><code>-1000 &lt;= Node.val &lt;= 1000</code></li>\n\t<li><code>-1000 &lt;= targetSum &lt;= 1000</code></li>\n</ul>\n\n<p>注意:本题与主站 113&nbsp;题相同:<a href=\"https://leetcode-cn.com/problems/path-sum-ii/\">https://leetcode-cn.com/problems/path-sum-ii/</a></p>\n",
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"difficulty": "Medium",
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"name": "Tree",
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"translatedName": "树",
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"name": "Depth-First Search",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public List<List<Integer>> pathSum(TreeNode root, int target) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def pathSum(self, root, target):\n \"\"\"\n :type root: TreeNode\n :type target: int\n :rtype: List[List[int]]\n \"\"\"",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** pathSum(struct TreeNode* root, int target, int* returnSize, int** returnColumnSizes){\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public IList<IList<int>> PathSum(TreeNode root, int target) {\n\n }\n}",
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{
"lang": "JavaScript",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} target\n * @return {number[][]}\n */\nvar pathSum = function(root, target) {\n\n};",
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"lang": "Ruby",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} target\n# @return {Integer[][]}\ndef path_sum(root, target)\n\nend",
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"lang": "Swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func pathSum(_ root: TreeNode?, _ target: Int) -> [[Int]] {\n\n }\n}",
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{
"lang": "Go",
"langSlug": "golang",
"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc pathSum(root *TreeNode, target int) [][]int {\n\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def pathSum(root: TreeNode, target: Int): List[List[Int]] = {\n\n }\n}",
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"lang": "Kotlin",
"langSlug": "kotlin",
"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun pathSum(root: TreeNode?, target: Int): List<List<Int>> {\n\n }\n}",
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"lang": "Rust",
"langSlug": "rust",
"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn path_sum(root: Option<Rc<RefCell<TreeNode>>>, target: i32) -> Vec<Vec<i32>> {\n\n }\n}",
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"lang": "PHP",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $target\n * @return Integer[][]\n */\n function pathSum($root, $target) {\n\n }\n}",
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"lang": "Racket",
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"code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (path-sum root target)\n (-> (or/c tree-node? #f) exact-integer? (listof (listof exact-integer?)))\n\n )",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec path_sum(Root :: #tree_node{} | null, Target :: integer()) -> [[integer()]].\npath_sum(Root, Target) ->\n .",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec path_sum(root :: TreeNode.t | nil, target :: integer) :: [[integer]]\n def path_sum(root, target) do\n\n end\nend",
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"sampleTestCase": "[5,4,8,11,null,13,4,7,2,null,null,5,1]\n22",
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