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https://gitee.com/coder-xiaomo/leetcode-problemset
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85 lines
10 KiB
JSON
85 lines
10 KiB
JSON
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"categoryTitle": "Database",
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"boundTopicId": 1060,
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"title": "Combine Two Tables",
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"titleSlug": "combine-two-tables",
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"content": "<p>Table: <code>Person</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| personId | int |\n| lastName | varchar |\n| firstName | varchar |\n+-------------+---------+\npersonId is the primary key column for this table.\nThis table contains information about the ID of some persons and their first and last names.\n</pre>\n\n<p> </p>\n\n<p>Table: <code>Address</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| addressId | int |\n| personId | int |\n| city | varchar |\n| state | varchar |\n+-------------+---------+\naddressId is the primary key column for this table.\nEach row of this table contains information about the city and state of one person with ID = PersonId.\n</pre>\n\n<p> </p>\n\n<p>Write an SQL query to report the first name, last name, city, and state of each person in the <code>Person</code> table. If the address of a <code>personId</code> is not present in the <code>Address</code> table, report <code>null</code> instead.</p>\n\n<p>Return the result table in <strong>any order</strong>.</p>\n\n<p>The query result format is in the following example.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nPerson table:\n+----------+----------+-----------+\n| personId | lastName | firstName |\n+----------+----------+-----------+\n| 1 | Wang | Allen |\n| 2 | Alice | Bob |\n+----------+----------+-----------+\nAddress table:\n+-----------+----------+---------------+------------+\n| addressId | personId | city | state |\n+-----------+----------+---------------+------------+\n| 1 | 2 | New York City | New York |\n| 2 | 3 | Leetcode | California |\n+-----------+----------+---------------+------------+\n<strong>Output:</strong> \n+-----------+----------+---------------+----------+\n| firstName | lastName | city | state |\n+-----------+----------+---------------+----------+\n| Allen | Wang | Null | Null |\n| Bob | Alice | New York City | New York |\n+-----------+----------+---------------+----------+\n<strong>Explanation:</strong> \nThere is no address in the address table for the personId = 1 so we return null in their city and state.\naddressId = 1 contains information about the address of personId = 2.\n</pre>\n",
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"translatedTitle": "组合两个表",
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"translatedContent": "<p>表: <code>Person</code></p>\n\n<pre>\n+-------------+---------+\n| 列名 | 类型 |\n+-------------+---------+\n| PersonId | int |\n| FirstName | varchar |\n| LastName | varchar |\n+-------------+---------+\npersonId是该表的主键列。\n该表包含一些人的ID和他们的姓和名的信息。\n</pre>\n\n<p> </p>\n\n<p>表: <code>Address</code></p>\n\n<pre>\n+-------------+---------+\n| 列名 | 类型 |\n+-------------+---------+\n| AddressId | int |\n| PersonId | int |\n| City | varchar |\n| State | varchar |\n+-------------+---------+\naddressId是该表的主键列。\n该表的每一行都包含一个ID = PersonId的人的城市和州的信息。\n</pre>\n\n<p> </p>\n\n<p>编写一个SQL查询来报告 <code>Person</code> 表中每个人的姓、名、城市和状态。如果 <code>personId</code> 的地址不在 <code>Address</code> 表中,则报告为空 <code>null</code> 。</p>\n\n<p>以 <strong>任意顺序</strong> 返回结果表。</p>\n\n<p>查询结果格式如下所示。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nPerson表:\n+----------+----------+-----------+\n| personId | lastName | firstName |\n+----------+----------+-----------+\n| 1 | Wang | Allen |\n| 2 | Alice | Bob |\n+----------+----------+-----------+\nAddress表:\n+-----------+----------+---------------+------------+\n| addressId | personId | city | state |\n+-----------+----------+---------------+------------+\n| 1 | 2 | New York City | New York |\n| 2 | 3 | Leetcode | California |\n+-----------+----------+---------------+------------+\n<strong>输出:</strong> \n+-----------+----------+---------------+----------+\n| firstName | lastName | city | state |\n+-----------+----------+---------------+----------+\n| Allen | Wang | Null | Null |\n| Bob | Alice | New York City | New York |\n+-----------+----------+---------------+----------+\n<strong>解释:</strong> \n地址表中没有 personId = 1 的地址,所以它们的城市和州返回null。\naddressId = 1 包含了 personId = 2 的地址信息。</pre>\n",
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"sampleTestCase": "{\"headers\":{\"Person\":[\"PersonId\",\"LastName\",\"FirstName\"],\"Address\":[\"AddressId\",\"PersonId\",\"City\",\"State\"]},\"rows\":{\"Person\":[[1,\"Wang\",\"Allen\"],[2,\"Alice\",\"Bob\"]],\"Address\":[[1,2,\"New York City\",\"New York\"],[2,3,\"Leetcode\",\"California\"]]}}",
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"Create table If Not Exists Person (personId int, firstName varchar(255), lastName varchar(255))",
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"Create table If Not Exists Address (addressId int, personId int, city varchar(255), state varchar(255))",
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"Truncate table Person",
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"insert into Person (personId, lastName, firstName) values ('1', 'Wang', 'Allen')",
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"insert into Person (personId, lastName, firstName) values ('2', 'Alice', 'Bob')",
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"Truncate table Address",
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"insert into Address (addressId, personId, city, state) values ('1', '2', 'New York City', 'New York')",
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"insert into Address (addressId, personId, city, state) values ('2', '3', 'Leetcode', 'California')"
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"exampleTestcases": "{\"headers\":{\"Person\":[\"personId\",\"lastName\",\"firstName\"],\"Address\":[\"addressId\",\"personId\",\"city\",\"state\"]},\"rows\":{\"Person\":[[1,\"Wang\",\"Allen\"],[2,\"Alice\",\"Bob\"]],\"Address\":[[1,2,\"New York City\",\"New York\"],[2,3,\"Leetcode\",\"California\"]]}}",
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