leetcode-problemset/leetcode-cn/originData/basic-calculator.json

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            "title": "Basic Calculator",
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            "content": "<p>Given a string <code>s</code> representing a valid expression, implement a basic calculator to evaluate it, and return <em>the result of the evaluation</em>.</p>\n\n<p><strong>Note:</strong> You are <strong>not</strong> allowed to use any built-in function which evaluates strings as mathematical expressions, such as <code>eval()</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;1 + 1&quot;\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot; 2-1 + 2 &quot;\n<strong>Output:</strong> 3\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;(1+(4+5+2)-3)+(6+8)&quot;\n<strong>Output:</strong> 23\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 3 * 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of digits, <code>&#39;+&#39;</code>, <code>&#39;-&#39;</code>, <code>&#39;(&#39;</code>, <code>&#39;)&#39;</code>, and <code>&#39; &#39;</code>.</li>\n\t<li><code>s</code> represents a valid expression.</li>\n\t<li><code>&#39;+&#39;</code> is <strong>not</strong> used as a unary operation (i.e., <code>&quot;+1&quot;</code> and <code>&quot;+(2 + 3)&quot;</code> is invalid).</li>\n\t<li><code>&#39;-&#39;</code> could be used as a unary operation (i.e., <code>&quot;-1&quot;</code> and <code>&quot;-(2 + 3)&quot;</code> is valid).</li>\n\t<li>There will be no two consecutive operators in the input.</li>\n\t<li>Every number and running calculation will fit in a signed 32-bit integer.</li>\n</ul>\n",
            "translatedTitle": "基本计算器",
            "translatedContent": "<p>给你一个字符串表达式 <code>s</code> ，请你实现一个基本计算器来计算并返回它的值。</p>\n\n<p>注意:不允许使用任何将字符串作为数学表达式计算的内置函数，比如 <code>eval()</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"1 + 1\"\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \" 2-1 + 2 \"\n<strong>输出：</strong>3\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"(1+(4+5+2)-3)+(6+8)\"\n<strong>输出：</strong>23\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 3&nbsp;* 10<sup>5</sup></code></li>\n\t<li><code>s</code> 由数字、<code>'+'</code>、<code>'-'</code>、<code>'('</code>、<code>')'</code>、和 <code>' '</code> 组成</li>\n\t<li><code>s</code> 表示一个有效的表达式</li>\n\t<li><font color=\"#c7254e\"><font face=\"Menlo, Monaco, Consolas, Courier New, monospace\"><span style=\"font-size:12.6px\"><span style=\"background-color:#f9f2f4\">'+'</span></span></font></font> 不能用作一元运算(例如， <font color=\"#c7254e\"><font face=\"Menlo, Monaco, Consolas, Courier New, monospace\"><span style=\"font-size:12.6px\"><span style=\"background-color:#f9f2f4\">\"+1\"</span></span></font></font>&nbsp;和 <code>\"+(2 + 3)\"</code>&nbsp;无效)</li>\n\t<li><font color=\"#c7254e\"><font face=\"Menlo, Monaco, Consolas, Courier New, monospace\"><span style=\"font-size:12.6px\"><span style=\"background-color:#f9f2f4\">'-'</span></span></font></font> 可以用作一元运算(即 <font color=\"#c7254e\"><font face=\"Menlo, Monaco, Consolas, Courier New, monospace\"><span style=\"font-size:12.6px\"><span style=\"background-color:#f9f2f4\">\"-1\"</span></span></font></font>&nbsp;和 <code>\"-(2 + 3)\"</code>&nbsp;是有效的)</li>\n\t<li>输入中不存在两个连续的操作符</li>\n\t<li>每个数字和运行的计算将适合于一个有符号的 32位 整数</li>\n</ul>\n",
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