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{
"data": {
"question": {
"questionId": "1000262",
"questionFrontendId": "剑指 Offer II 026",
"categoryTitle": "LCOF2",
"boundTopicId": 910174,
"title": "重排链表",
"titleSlug": "LGjMqU",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "重排链表",
"translatedContent": "<p>给定一个单链表 <code>L</code><em> </em>的头节点 <code>head</code> ,单链表 <code>L</code> 表示为:</p>\n\n<p><code>&nbsp;L<sub>0&nbsp;</sub>&rarr; L<sub>1&nbsp;</sub>&rarr; &hellip; &rarr; L<sub>n-1&nbsp;</sub>&rarr; L<sub>n&nbsp;</sub></code><br />\n请将其重新排列后变为</p>\n\n<p><code>L<sub>0&nbsp;</sub>&rarr;&nbsp;L<sub>n&nbsp;</sub>&rarr;&nbsp;L<sub>1&nbsp;</sub>&rarr;&nbsp;L<sub>n-1&nbsp;</sub>&rarr;&nbsp;L<sub>2&nbsp;</sub>&rarr;&nbsp;L<sub>n-2&nbsp;</sub>&rarr; &hellip;</code></p>\n\n<p>不能只是单纯的改变节点内部的值,而是需要实际的进行节点交换。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626420311-PkUiGI-image.png\" style=\"width: 240px; \" /></p>\n\n<pre>\n<strong>输入: </strong>head = [1,2,3,4]\n<strong>输出: </strong>[1,4,2,3]</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<p><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626420320-YUiulT-image.png\" style=\"width: 320px; \" /></p>\n\n<pre>\n<strong>输入: </strong>head = [1,2,3,4,5]\n<strong>输出: </strong>[1,5,2,4,3]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>链表的长度范围为 <code>[1, 5 * 10<sup>4</sup>]</code></li>\n\t<li><code>1 &lt;= node.val &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 143&nbsp;题相同:<a href=\"https://leetcode-cn.com/problems/reorder-list/\">https://leetcode-cn.com/problems/reorder-list/</a>&nbsp;</p>\n",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * ListNode *next;\n * ListNode() : val(0), next(nullptr) {}\n * ListNode(int x) : val(x), next(nullptr) {}\n * ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n void reorderList(ListNode* head) {\n\n }\n};",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * int val;\n * ListNode next;\n * ListNode() {}\n * ListNode(int val) { this.val = val; }\n * ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n public void reorderList(ListNode head) {\n\n }\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution(object):\n def reorderList(self, head):\n \"\"\"\n :type head: ListNode\n :rtype: None Do not return anything, modify head in-place instead.\n \"\"\"",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n def reorderList(self, head: ListNode) -> None:\n \"\"\"\n Do not return anything, modify head in-place instead.\n \"\"\"",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public int val;\n * public ListNode next;\n * public ListNode(int val=0, ListNode next=null) {\n * this.val = val;\n * this.next = next;\n * }\n * }\n */\npublic class Solution {\n public void ReorderList(ListNode head) {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {void} Do not return anything, modify head in-place instead.\n */\nvar reorderList = function(head) {\n\n};",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public var val: Int\n * public var next: ListNode?\n * public init() { self.val = 0; self.next = nil; }\n * public init(_ val: Int) { self.val = val; self.next = nil; }\n * public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n func reorderList(_ head: ListNode?) {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n * Val int\n * Next *ListNode\n * }\n */\nfunc reorderList(head *ListNode) {\n\n}",
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"lang": "Racket",
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"code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n (list-node val #f))\n\n|#\n\n(define/contract (reorder-list head)\n (-> (or/c list-node? #f) void?)\n\n )",
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