mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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180 lines
20 KiB
JSON
180 lines
20 KiB
JSON
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"title": "01 Matrix",
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"content": "<p>Given an <code>m x n</code> binary matrix <code>mat</code>, return <em>the distance of the nearest </em><code>0</code><em> for each cell</em>.</p>\n\n<p>The distance between two adjacent cells is <code>1</code>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/24/01-1-grid.jpg\" style=\"width: 253px; height: 253px;\" />\n<pre>\n<strong>Input:</strong> mat = [[0,0,0],[0,1,0],[0,0,0]]\n<strong>Output:</strong> [[0,0,0],[0,1,0],[0,0,0]]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/24/01-2-grid.jpg\" style=\"width: 253px; height: 253px;\" />\n<pre>\n<strong>Input:</strong> mat = [[0,0,0],[0,1,0],[1,1,1]]\n<strong>Output:</strong> [[0,0,0],[0,1,0],[1,2,1]]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 <= m, n <= 10<sup>4</sup></code></li>\n\t<li><code>1 <= m * n <= 10<sup>4</sup></code></li>\n\t<li><code>mat[i][j]</code> is either <code>0</code> or <code>1</code>.</li>\n\t<li>There is at least one <code>0</code> in <code>mat</code>.</li>\n</ul>\n",
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"translatedTitle": "01 矩阵",
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