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33 lines
1.4 KiB
HTML
33 lines
1.4 KiB
HTML
给你一个 <code>m x n</code> 的矩阵 <code>board</code> ，由若干字符 <code>'X'</code> 和 <code>'O'</code> ，找到所有被 <code>'X'</code> 围绕的区域，并将这些区域里所有的 <code>'O'</code> 用 <code>'X'</code> 填充。
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<div class="original__bRMd">
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<div>
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<p> </p>
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<p><strong>示例 1：</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2021/02/19/xogrid.jpg" style="width: 550px; height: 237px;" />
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<pre>
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<strong>输入：</strong>board = [["X","X","X","X"],["X","O","O","X"],["X","X","O","X"],["X","O","X","X"]]
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<strong>输出：</strong>[["X","X","X","X"],["X","X","X","X"],["X","X","X","X"],["X","O","X","X"]]
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<strong>解释：</strong>被围绕的区间不会存在于边界上，换句话说，任何边界上的 <code>'O'</code> 都不会被填充为 <code>'X'</code>。 任何不在边界上，或不与边界上的 <code>'O'</code> 相连的 <code>'O'</code> 最终都会被填充为 <code>'X'</code>。如果两个元素在水平或垂直方向相邻，则称它们是“相连”的。
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</pre>
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<p><strong>示例 2：</strong></p>
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<pre>
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<strong>输入：</strong>board = [["X"]]
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<strong>输出：</strong>[["X"]]
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li><code>m == board.length</code></li>
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<li><code>n == board[i].length</code></li>
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<li><code>1 <= m, n <= 200</code></li>
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<li><code>board[i][j]</code> 为 <code>'X'</code> 或 <code>'O'</code></li>
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</ul>
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</div>
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</div>
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