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<p>给定一个 <em>n&nbsp;</em>×&nbsp;<em>n</em> 的二维矩阵&nbsp;<code>matrix</code> 表示一个图像。请你将图像顺时针旋转 90 度。</p>
<p>你必须在<strong><a href="https://baike.baidu.com/item/%E5%8E%9F%E5%9C%B0%E7%AE%97%E6%B3%95" target="_blank"> 原地</a></strong> 旋转图像,这意味着你需要直接修改输入的二维矩阵。<strong>请不要 </strong>使用另一个矩阵来旋转图像。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/08/28/mat1.jpg" style="height: 188px; width: 500px;" />
<pre>
<strong>输入:</strong>matrix = [[1,2,3],[4,5,6],[7,8,9]]
<strong>输出:</strong>[[7,4,1],[8,5,2],[9,6,3]]
</pre>
<p><strong>示例 2</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/08/28/mat2.jpg" style="height: 201px; width: 500px;" />
<pre>
<strong>输入:</strong>matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
<strong>输出:</strong>[[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>n == matrix.length == matrix[i].length</code></li>
<li><code>1 &lt;= n &lt;= 20</code></li>
<li><code>-1000 &lt;= matrix[i][j] &lt;= 1000</code></li>
</ul>
<p>&nbsp;</p>