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leetcode-problemset/leetcode-cn/problem (Chinese)/找到所有好字符串 [find-all-good-strings].html
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<p>给你两个长度为 <code>n</code>&nbsp;的字符串&nbsp;<code>s1</code>&nbsp;<code>s2</code>&nbsp;,以及一个字符串&nbsp;<code>evil</code>&nbsp;。请你返回 <strong>好字符串&nbsp;</strong>的数目。</p>
<p><strong>好字符串</strong>&nbsp;的定义为:它的长度为&nbsp;<code>n</code>&nbsp;,字典序大于等于&nbsp;<code>s1</code>&nbsp;,字典序小于等于&nbsp;<code>s2</code>&nbsp;,且不包含&nbsp;<code>evil</code>&nbsp;为子字符串。</p>
<p>由于答案可能很大,请你返回答案对 10^9 + 7 取余的结果。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre><strong>输入:</strong>n = 2, s1 = &quot;aa&quot;, s2 = &quot;da&quot;, evil = &quot;b&quot;
<strong>输出:</strong>51
<strong>解释:</strong>总共有 25 个以 &#39;a&#39; 开头的好字符串:&quot;aa&quot;&quot;ac&quot;&quot;ad&quot;...&quot;az&quot;。还有 25 个以 &#39;c&#39; 开头的好字符串:&quot;ca&quot;&quot;cc&quot;&quot;cd&quot;...&quot;cz&quot;。最后,还有一个以 &#39;d&#39; 开头的好字符串:&quot;da&quot;
</pre>
<p><strong>示例 2</strong></p>
<pre><strong>输入:</strong>n = 8, s1 = &quot;leetcode&quot;, s2 = &quot;leetgoes&quot;, evil = &quot;leet&quot;
<strong>输出:</strong>0
<strong>解释:</strong>所有字典序大于等于 s1 且小于等于 s2 的字符串都以 evil 字符串 &quot;leet&quot; 开头。所以没有好字符串。
</pre>
<p><strong>示例 3</strong></p>
<pre><strong>输入:</strong>n = 2, s1 = &quot;gx&quot;, s2 = &quot;gz&quot;, evil = &quot;x&quot;
<strong>输出:</strong>2
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>s1.length == n</code></li>
<li><code>s2.length == n</code></li>
<li><code>s1 &lt;= s2</code></li>
<li><code>1 &lt;= n &lt;= 500</code></li>
<li><code>1 &lt;= evil.length &lt;= 50</code></li>
<li>所有字符串都只包含小写英文字母。</li>
</ul>